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natima [27]
2 years ago
5

Mila wants to buy a scooter for Rs 62,000 . She has only Rs 19,000 with her, so she decides to take a loan from a bank for the r

emaining amount. The bank offers Mini three loan schemes as shown below. Mini has to return the loan amount with interest in equal monthly instalments
1) How much money does mila take as loan from the bank?

a) Rs 62,000
b) Rs 44,000
c) Rs 45,000
d) Rs 43,000​

Mathematics
2 answers:
Aneli [31]2 years ago
8 0

Answer:

Scheme a 45000 is the answer

levacccp [35]2 years ago
7 0
<h2>Answer </h2><h2>is D </h2><h2>Rs.43,000</h2><h2>I hope this answer may be right </h2>
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x^2 + x^5 + C.

Step-by-step explanation:

∫2x + 5x^4 dx

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= x^2 + x^5 + C.

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76.<br>175/50<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B175%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B50%7D%20%
kramer

Answer:

Step-by-step explanation:

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50  = 5 * 5 * 2

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3. Using the sample size of 800 and the proportion 0.47, calculate the margin of error associated with the estimate of the propo
salantis [7]

Answer:

ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And if we replace the values obtained we got this:

ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346  

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apparently subtracting 6

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