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Butoxors [25]
3 years ago
11

A area of a triangle with 6m and 8m​

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

24

Step-by-step explanation:6 x 8 = 48 = 48/ 1/2 =24

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Find an equivalent ratio.<br>7:13​
Sliva [168]

Answer:

7/20

Step-by-step explanation:

5 0
3 years ago
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100 POINTS!!! ONLY 1 QUESTION! WILL GIVE BRAINLIEST. Please EXPLAIN how you got the answer
77julia77 [94]

Answer:

A

Step-by-step explanation:

its hard to explain but pretty much if you didn't know the ^x+1 is the x intercept except when its graphed its no marked at (1,0) its mark ate (-1,0) because it always takes the inverse

if you go over to the right 3 then your adding 3 to the x intercept or subtracting 3 from ^x+1 so it would be ^x-2

the y intercept part is easy all you have to do is subtract 2 from the y intercept so it would be +2

hope this helps :D

5 0
3 years ago
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Writing an equation and drawing its graph to model a real-world situation ​
Mariana [72]

Answer:

A = B + 15

Step-by-step explanation:

Let Diane sold B books in one hour,

Additional earning by selling 1 book = 1$

Additional earning by selling B books = Number of books sold × Additional earning by selling one book

= B × ($1.00)

= $B

Fixed earning of Diane in one hour of part time = $15

Total earnings = B + 15

A = B + 15

Table to find the input-output values for the graph,

A      15      16        17      18

B       0        1          2       3

Now we can plot the points on the graph.

7 0
3 years ago
HELP PLZZZZ! thank you
Setler79 [48]

1. Same length.

2.vertically opposite angle.

3.BAC =BDE

4.AC = DE

Hope this helps you ___!!❤

3 0
3 years ago
if two pyramids are similar and the ratio between the lengths of their edges is 2;7 what is the ratio of their volumes? ...?
jok3333 [9.3K]
<span>The answer is 8:343.

</span>We can use Galileo's square cube law to calculate the ratio between two similar pyramids. The law is used to describe the change of the area or the volume of the shape when their dimensions increase or decrease:
\frac{V_1}{V_2} =( \frac{l_1}{l_2} )^{3} \\<span>
</span><span><span> <span> <span> <span> <span> <span> <span> <span> <span> <span> <span> </span></span></span></span></span></span></span></span></span> </span></span> </span>
V₁ and V₂ - volumes of pyramids,
l₁ and <span>l</span>₂ - the edges of pyramids.
<span>
</span>\frac{V_1}{V_2} =( \frac{l_1}{l_2} )^{3} \\ \frac{V_1}{V_2} =( \frac{2}{7} )^{3} \\ \frac{V_1}{V_2} = \frac{2^{3}}{7^{3}} \\ \frac{V_1}{V_2} = \frac{8}{343} \\<span>
</span>
3 0
3 years ago
Read 2 more answers
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