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3 years ago

What number must you multiply both sides of 3/4a=24 by to get equivalent equation a=32??

Mathematics

1 answer:

Mamont248 [21]3 years ago

3 0

4 because 4 times 24 equals 96 then 96 divided by 3 equals 32

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Help me with the question of O.math

Mashutka [201]

Answer:

Step-by-step explanation:

2*1+1+2*2+1+2*3+1+2*4+1=24

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3 years ago

X^{2} - 8x + 7 = 0<br> Solve by completing the square. Also can you include steps?

iren [92.7K]

Answer:

{1, 7}

Step-by-step explanation:

Start with x^2 - 8x + 7 = 0.

We want to modify the first two terms to resemble x^2 - ax + b - b, where a is the coefficient (here -8) of the x term and b is the square of half of a.

Here, a = -8. Half of that is -4. The square of -4 is 16, and this is the value of b.

Write out x^2 - 8x as x^2 - 8x + 16 - 16. This is the perfect square of -4, added to x^2 - 8x and then subtracted from the result

Then the original equation, x^2 - 8x + 7 = 0, can be rewritten as:

x^2 - 8x + 16 - 16 + 7 = 0, and then as (x - 4)^2 - 9, or (x - 4)^2 = 9.

We want to solve this result for x. To do this, take the square root of both sides:

x - 4 = ±√9, or x - 4 = ±3.

Adding 4 to both sides, we get:

x = 4 ± 3. Thus, the solutions are x = 4 + 3 = 7 and x = 4 - 3 = 1.

6 0

4 years ago

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The sum of two numbers is 56. Their product is 108. Find the larger number?

lakkis [162]

Answer:

Step-by-step explanation:

The two numbers are 54 and 2

Their sum = 54 + 2 = 56

Their product = 54 x 2 = 108

4 0

3 years ago

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Gerald would like to add a dental and vision option to the health insurance plan he purchased through his employer. In addition

Genrish500 [490]

B. $145.50
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3 years ago

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What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

AlexFokin [52]

Answer:

The standard form of quadratic equation is $x^2-16x-36=0$

The factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

Step-by-step explanation:

Given equation $x^2-6=16x+30$

We have to write in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as $ax^2+bx+c=0$

Consider $x^2-6=16x+30$

Taking all terms to left side, we have,

$x^2-6-16x-30=0$

Adding like terms, we have,

$x^2-16x-36=0$

Now we will factorize it.

We will solve the quadratic equation $x^2-16x-36=0$ using middle term splitting method,

-16x can be written as -18x+2x

$x^2-16x-36=0$ becomes

$\Rightarrow x^2-18x+2x-36=0$

Taking x common from first two terms and 2 common from last two terms we have,

$\Rightarrow x(x-18)+2(x-18)=0$

$\Rightarrow (x+2)(x-18)=0$

Thus, the factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

4 0

3 years ago

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