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Nata [24]
3 years ago
14

Write a ratio that is equivalent to 3:5, other than 3:5 itself

Mathematics
1 answer:
natulia [17]3 years ago
7 0

Answer:

9:15

Step-by-step explanation:

\frac{3*3}{5*3}=\frac{9}{15}=9:15

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Answer:

Your answer is :

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Step-by-step explanation:

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2 years ago
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Please help me with the below question.
Snezhnost [94]

6a. By the convolution theorem,

L\{t^3\star e^{5t}\} = L\{t^3\} \times L\{e^{5t}\} = \dfrac6{s^4} \times \dfrac1{s-5} = \boxed{\dfrac5{s^4(s-5)}}

6b. Similarly,

L\{e^{3t}\star \cos(t)\} = L\{e^{3t}\} \times L\{\cos(t)\} = \dfrac1{s-3} \times \dfrac s{1+s^2} = \boxed{\dfrac s{(s-3)(s^2+1)}}

7. Take the Laplace transform of both sides, noting that the integral is the convolution of e^t and f(t).

\displaystyle f(t) = 3 - 4 \int_0^t e^\tau f(t - \tau) \, d\tau

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where g(t) = e^t. Then G(s) = \frac1{s-1}, and

F(s) = \dfrac3s - \dfrac4{s-1} F(s) \implies F(s) = \dfrac{\frac3s}{\frac{s+3}{s-1}} = 3\dfrac{s-1}{s(s+3)}

We have the partial fraction decomposition,

\dfrac{s-1}{s(s+3)} = \dfrac13 \left(-\dfrac1s + \dfrac4{s+3}\right)

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F(s) = -\dfrac1s + \dfrac4{s+3}

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6 0
2 years ago
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7 0
3 years ago
The four folded parts of an envelope are opened up to create this figure. What is the surface area of one side of the unfolded e
vichka [17]

Answer:

Option C. 50 square centimeters

Step-by-step explanation:

we know that

The surface area is equal to the area of four triangles plus the area of rectangle

so

SA=2[\frac{1}{2}(4)(2)]+2[\frac{1}{2}(6)(3)]+(6)(4)

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SA=50\ cm^{2}

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3 years ago
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fomenos
Hey mate l think it is 

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