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Vlad [161]
3 years ago
15

What is the range of the function y = x2? x20 all real numbers y20

Mathematics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

the range is y>0

Step-by-step explanation:

y=(x-0) 2+0

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Factor this polynomial expression.
Zanzabum

Answer:

B) 2(x+3)(x+3)

Step-by-step explanation:

4 0
3 years ago
In 2011, Americans spent approximately $50.9 billion on their pets. Of this amount, $14.1 billion was for veterinarian bills. Wh
alex41 [277]

Answer: The percent of the total was spent on veterinarian bills is 27.70% ( approx).

Step-by-step explanation:

Given, In 2011, Americans spent approximately $50.9 billion on their pets.

i.e. Total amount they spent on pets = $50.9 billion

Amount spent for veterinarian bills.  = $14.1 billion was for veterinarian bills.

Then, the percent of the total was spent on veterinarian bills would be :

\dfrac{\text{Amount spent for veterinarian bills. }}{\text{Total amount they spent on pets}}\times100\\\\=\dfrac{14.1}{50.9}\times100\\\\=27.7013752456\approx27.70\%

Hence, the percent of the total was spent on veterinarian bills is 27.70% (approx).

5 0
4 years ago
A line with a slope of 4 passes through the point 2,1.What is the equation of the line?
True [87]
Y= mx+b
m= the slope and b=the y intercept
so if you plus in the info you have it would be
y=4x+1
5 0
3 years ago
What is 3 miles per minute expressed in feet per minute? Recall that 1 mile is 5,280 feet.
aliina [53]

Answer: 15,840 Ft.

Step-by-step explanation: Brainliest, Please and Thank you :)

6 0
3 years ago
Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial t
jekas [21]

Answer:

(12.1409, 14.0591

Step-by-step explanation:

Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.

Group   Group One     Group Two  

Mean 87.600 74.500

SD 1.000 1.500

SEM 0.316 0.433

N 10      12    

The mean of Group One minus Group Two equals 13.100

standard error of difference = 0.556

 90% confidence interval of this difference:  

(13.1-1.725*0.556,13.1+1.725*0.556)\\=(12.1409, 14.0591)

  t = 23.5520

 df = 20

4 0
3 years ago
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