Question

Find the dy/dxy= sin²x/cos²x​

Answer 1

Answer:

d y dx=0

Explanation:

From the given

y=sin2x+cos2x

The right side of the equation is

=1

y=1

d y d x=d d x(1)=0

or we can do it this way.

y = sin2x+cos2x

d y d x=2

⋅(sinx)2−1

⋅

d d x(sinx)+2

(cosx)2−1 d d x(cosx)

d y d x=2⋅

sinx⋅cosx+2⋅cosx⋅(−sinx)

dydx=2⋅sinx⋅cosx−2⋅sinx⋅cosx

dydx=0

God bless....I hope the explanation is useful.