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Stolb23 [73]
2 years ago
15

What is the measure (in radians) of central angle in the circle below?

Mathematics
1 answer:
kati45 [8]2 years ago
3 0

Answer:

∅ = 5 radians

Step-by-step explanation:

Arc.Length=2\pi r(\frac{Ctrl.Angle}{360} )

Ctrl.Angle=\frac{360(Arc.length)}{2\pi r}

∅ =\frac{(360)(15)}{2\pi (3)}

∅ = 286.48°

In radians:

∅ = (286.48)(3.1416)/180 = 5 radians

Hope this helps

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Please help me ASAP! Triangle ABC is located at A (2, 3), B (4, 4), and C (6, 3). Zackary says that triangle ABC is an isosceles
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<h2>Hello!</h2>

The answer is:

The second option,

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<h2>Why?</h2>

To identify which type of triangle is the triangle formed by the given points, first, we need to calculate the distance between the points.

So, finding the distances we have:

From A to B: (2,3) and (4,4)

distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(4-2)^{2} +(4-3)^{2}}=\sqrt{2^{2} +1^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units

From B to C: (4,4) and (6,3)

distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(6-4)^{2} +(3-4)^{2}}=\sqrt{2^{2} +(-1)^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units

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Zackery, because AB=BC

Have a nice day!

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