Hello!
The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³
Data: (Cone)
h (height) = 12 cm
r (radius) = 4 cm (The diameter is 8 being twice the radius)
Adopting: 
V (volume) = ?
Solving: (Cone volume)




Note: Now, let's find the volume of a hemisphere.
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 4 cm
Adopting: 
If: We know that the volume of a sphere is
, but we have a hemisphere, so the formula will be half the volume of the hemisphere 
Formula: (Volume of the hemisphere)

Solving:





What is the approximate volume of this figure?
Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)
Volume of the figure = cone volume + hemisphere volume
Volume of the figure = 200.96 cm³ + 133.97 cm³

Answer:
The volume of the figure is approximately 335 cm³
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I Hope this helps, greetings ... Dexteright02! =)