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2 years ago

Solve expression completely.

Mathematics

1 answer:

SSSSS [86.1K]2 years ago

6 0

Answer:

Step-by-step explanation:

(9 - 3)² - (5 . 4)⁰

= (6)² - (20)⁰

= 36 - 1

= 35

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The difference of two numbers is equal to 0.6. Their quotient is also 0.6. What are the numbers? There are 4

Makovka662 [10]

Let the two numbers be represented by x and y. The problem statement gives rise to two sets of equations.
x - y = 0.6
y/x = 0.6 . . . . . . . assuming x is the larger of the two numbers
or
x/y = 0.6 . . . . . . . assuming y has the larger magnitude

The solution of the first pair of equations is
(x, y) = (1.5, 0.9)

The solution of the first and last equations is
(x, y) = (-0.9, -1.5)

The pairs of numbers could be {0.9, 1.5} or {-1.5, -0.9}.

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2 years ago

Find the mean of 1,0,10,7,13,2,9,15,0,3

svet-max [94.6K]

1,0,10,7,13,2,9,15,0,3/ 10
=60/10
=6

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2 years ago

Read 2 more answers

If the distance traveled is (4s3 - 6s² + 4s + 14) miles and the rate is (s + 1) mph, write an expression, in hours, for the time

BartSMP [9]

The equation for time is URM:

$time = \frac{distance}{speed \: (rate)}$

$t(s) = \frac{4s {}^{3} - 6s {}^{2} + 4s + 14}{s + 1} = \frac{2(s + 1)(2s {}^{2} - 5s + 7) }{s + 1} \\ t(s) = 2(2s {}^{2} - 5s + 7) \\ t(s) = 4s {}^{2} - 10s + 14$

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7 months ago

Which of the following is a proportion? (Image)

Ganezh [65]

Answer:

the second one

Step-by-step explanation:

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1 year ago

Does anyone know this?

Stels [109]

Every hexagon clearly has 6 sides. Nevertheless, every time you "glue" two hexagons together, you "lose" 2 sides to your count, because the sides where the two hexagons meet are not exterior sides anymore, and so they are not taken into account in our counting.

Also observe that with n hexagons you have n-1 points of contact between hexagons.

Since every hexagon has 6 sides and every gluing point takes away 2 sides, the number of exterior sides with n hexagons is

$s(n)=6n - 2(n-1) = 6n-2n+2=4n+2$

Let's plug some values for n:

$s(1) = 4\cdot 1 + 2 = 4+2 = 6$
$s(2) = 4\cdot 2 + 2 = 8+2 = 10$
$s(3) = 4\cdot 3 + 2 = 12+2 = 14$
$s(4) = 4\cdot 4 + 2 = 16+2 = 18$

You can check that these values are correct by counting the sides on the figure you have.

Finally, we can count the sides of a train with 10 hexagons by plugging n=10 in our formula:

$s(10) = 4\cdot 10 + 2 = 40 + 2 = 42$

Note: the numbers we've given are the number of sides that form the perimeter. So, the actual perimeters are the number of sides multiplied by the length of the side itself: if we let $s$ be the length of the side, the perimeters will be $6s,\ 10s,\ 14s,\ 18s$ for the first 4 trains, and $42s$ for the 10-hexagon train.

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2 years ago