Answer:
sec A = 5/4
Step-by-step explanation:
Sec of an angle is hypotenuse/adjacent side
In your problem, sec A = 25/20 = 5/4
It helps if you can draw a figure of the problem. Make sure you memorize the definition of each trig function
Check the picture below.
now, the midsegment of a triangle, besides being half the base, we have to bear in mind that is a "mid" segment, is a segment that lies half-way along the segments it touches.
so for the triangle above, well, the midsegment DE is cutting the segment BC it two equal halves, BE and EC, that means that 
.
3x² + 2x - 4 = 0
Δ = b² - 4.a.c
Δ = 2² - 4 . 3 . -4
Δ = 4 - 4. 3 . -4
Δ = 52
x = (-b +- √Δ)/2a
x' = (-2 + √52)/2.3
x'' = (-2 - √52)/2.3
x' = 0,8685170918213297
x'' = -1,5351837584879966
2 Decimal places
x' = 0,87
x'' = -1,54
This is the difference of 2 squares
square root of a^6 = a^3
and square root of 25 b^2 = 5b so we get
(a^3 + 5b)(a^3 - 5b)
Thats the answer
