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2 years ago

Someone please help me.

Mathematics

1 answer:

Sonja [21]2 years ago

5 0

Answer:

EBCG

Step-by-step explanation:

1) 50 - 87 = 23

2) 12 - 24= 288

3) 38.25 + 11.75= 50

4) 7 divided by 168= 24

You might be interested in

(−8k+1)(−8k+1) standard form

kifflom [539]

Answer:

64k^2 - 16k +1

Step-by-step explanation:

We can rewrite this as

(-8k+1) ^2

We know that (a+b)^2 = a^2 +2ab +b^2

Let a = -8k and b = 1

(-8k+1) = (-8k)^2 +2*(-8k)(1) + 1^2

=64k^2 - 16k +1

3 0

3 years ago

Read 2 more answers

3) There were 35 children and 10 adults at a barbeque.

Mila [183]

Answer:

3. a. 10:35= 2:7

b.35:45=7:9

c.40:50=4:5

7 0

2 years ago

How many balls in one pound of 00 buckshot?

QveST [7]

12...................

8 0

2 years ago

Nathan took his car in for service and repairs. He had a coupon for 10% off.

igor_vitrenko [27]

Answer:

$594.21

Step-by-step explanation:

Because 254.58 + 333.90+ 64.42= $622.87

and 10 off of $622.87 = $560.58

and 6% sales tax to $560.58 = $594.21

5 0

2 years ago

An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

Point a:

The Expected value or the mean value of X with set of possible values D, denoted by E(X) or μ is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by E[h(X)] is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

Point b:

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and E(X) = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

4 0

3 years ago