Answer:
cant see the picture dude
Step-by-step explanation:
<span>y = slope*x + y-intercept;
</span>We can rewrite our equation in a shorter form : y = mx + b;
y = x + 2 ; m1 = 2 and b1 = 2;
y = -x + 6; m2 = -1 and b2 = 6;
<span>Set the two equations for y equal to each other:
</span>x + 2 = -x + 6 ;
<span>Solve for x. This will be the x-coordinate for the point of intersection:
</span>2x = 4;
x = 2;
<span>Use this x-coordinate and plug it into either of the original equations for the lines and solve for y. This will be the y-coordinate of the point of intersection:
</span>y = 2 + 2 ;
y = 4;
<span>The point of intersection for these two lines is (2 , 4).</span>
Answer:
Option B: 
Step-by-step explanation:
The parabola has its concavity downwards, so we need a function in the model:
With a negative value of 'a'
The vertex is (0,0), so we have that:
The x-coordinate of the vertex is given by the equation:
So we have a function in the model:
With a < 0
The only option with this format is B:
The graph of the function contains the points (0,-7), (1,-9), and (3,-1) is incorrect
it contains all the points except the last set...(3,-1)
y = -2x - 7
-1 = -2(3) - 7
-1 = -6-7
-1 = - 13 (incorrect)
Answer:
4y²-1/4 is the required answer
Step-by-step explanation:
