Answer:
1 minus 1 is 0
Step-by-step explanation:
1-1 equals 0
Answer: Scientific Notation is the expression of a number n in the form a∗10b. where a is an integer such that 1≤|a|<10. and b is an integer too. Multiplication: To multiply numbers in scientific notation, multiply the decimal numbers. Then add the exponents of the powers of 10.
Step-by-step explanation:
If you multiple 128 by 6 you will get your answer of 768.
The slope of the given line is found from the coefficient of x after dividing the equation by 2.
.. y = -3x +4
The given line has slope -3.
A perpendicular line will have a slope that is the negative reciprocal of this:
.. -1/(-3) = 1/3
This corresponds to your 3rd choice.
Answer:
a) Objective function (minimize cost):

Restrictions
Proteins per pound: 
Vitamins per pound: 
Non-negative values: 
b) Attached
c) The optimum solution (minimum cost) is 0 pounds of ingredient A and 0.75 pounds of ingredient B. The cost is $0.15 per ration.
d) The optimum solution changes. The cost is now 0 pounds of ingredient A and 0.625 pounds of ingredient B. The cost is $0.125 per ration.
Step-by-step explanation:
a) The LP formulation for this problem is:
Objective function (minimize cost):

Restrictions
Proteins per pound: 
Vitamins per pound: 
Non-negative values: 
b) The feasible region is attached.
c) We have 3 corner points. In one of them lies the optimal solution.
Corner A=0 B=0.75

Corner A=0.5 B=0.5

Corner A=0.75 B=0

The optimum solution (minimum cost) is 0 pounds of ingredient A and 0.75 pounds of ingredient B. The cost is $0.15 per ration.
d) If the company requires only 5 units of vitamins per pound rather than 6, one of the restrictions change.
The feasible region changes two of its three corners:
Corner A=0 B=0.625

Corner A=0.583 B=0.333

Corner A=0.75 B=0

The optimum solution changes. The cost is now 0 pounds of ingredient A and 0.625 pounds of ingredient B. The cost is $0.125 per ration.