Let w= the length of the side perpendicular to the barn
300-2w= length of the side parallel to the barn
A=w(300-2w)
A=-2w^2+300w
The formula for the w-value of maximum is:
=-b/2a
thus our value will be:
300/4
=75
and
300-2(75)
=150
thus the dimensions to maximize the area is 75 by 150
For the question, your answer would be the first one; It doesn't exist.
Not sure what equation you're looking for, but against the current he goes 2 mph and with he goes 9mph, so 9-2=7mph difference between them, divided by 2 = 3.5 mph of the current. So in this case, James can paddle 2+3.5= 5.5 mph in still water and the current moves at 3.5 mph.
James can paddle 5.5 mph
The current moves at 3.5 mph
Equation: speed = 5.5 + 3.5x where x can equal -1, 0, or 1 depending on whether James is going with the current (x = 1), without the current (x = 0), or against the current (x = -1)
P(e)=number of evens/number of numbers :)
P(e)=3/6=1/2
Answer:
you have it done? what do you need
Step-by-step explanation: