Answer:
First choice.
Step-by-step explanation:
You could plug in the choices to see which would make all the 3 equations true.
Let's start with (x=2,y=-6,z=1):
2x+y-z=-3
2(2)+-6-1=-3
4-6-1=-3
-2-1=-3
-3=-3 is true so the first choice satisfies the first equation.
5x-2y+2z=24
5(2)-2(-6)+2(1)=24
10+12+2=24
24=24 is true so the first choice satisfies the second equation.
3x-z=5
3(2)-1=5
6-1=5
5=5 is true so the first choice satisfies the third equation.
We don't have to go any further since we found the solution.
---------Another way.
Multiply the first equation by 2 and add equation 1 and equation 2 together.
2(2x+y-z=-3)
4x+2y-2z=-6 is the first equation multiplied by 2.
5x-2y+2z=24
----------------------Add the equations together:
9x+0+0=18
9x=18
Divide both sides by 9:
x=18/9
x=2
Using the third equation along with x=2 we can find z.
3x-z=5 with x=2:
3(2)-z=5
6-z=5
Add z on both sides:
6=5+z
Subtract 5 on both sides:
1=z
Now using the first equation along with 2x+y-z=-3 with x=2 and z=1:
2(2)+y-1=-3
4+y-1=-3
3+y=-3
Subtract 3 on both sides:
y=-6
So the solution is (x=2,y=-6,z=1).
Slope = rise/run = 10/50 = 1/5
Answer:
The group's claim is not supported at 1% significance level.
Step-by-step explanation:
given that a local group claims that the police issue more than 60 speeding tickets a day in thire area
The data they collected for 2 weeks is given below:
70 48 41 68 69 55 70
57 60 83 32 60 72 58
Std error of mean = 
(Right tailed test at 1% significance level)
Mean difference = 0.10
Test statistic t with df 13 = mean difference/std error
= 0.029
p value = 0.4886
Since p >0.01, we accept null hypothesis
The group's claim is not supported at 1% significance level.
Answer:
is 3/7
Step-by-step explanation:
That would depend on the size of your classroom. but, typically the answer is no
