Answer:
numbers are 24 and 210
Step-by-step explanation:
the number are : 24(2x2x2x3) and 210 (3x2x5x7)
GCF of 24 and 210 is 6
LCM of 24 and 210 is 840
Volume of a cylinder is pi*r^2*h where r = radius and h = height
so 3^2*6*pi = 9*6*pi = 54pi
54 pi is the answer. mark me brainliest please!
Answer:
The half-life of the radioactive substance is of 3.25 days.
Step-by-step explanation:
The amount of radioactive substance is proportional to the number of counts per minute:
This means that the amount is given by the following differential equation:

In which k is the decay rate.
The solution is:

In which Q(0) is the initial amount:
8000 counts per minute on a Geiger counter at a certain time
This means that 
500 counts per minute 13 days later.
This means that
. We use this to find k.







So

Determine the half-life of the radioactive substance.
This is t for which Q(t) = 0.5Q(0). So







The half-life of the radioactive substance is of 3.25 days.
I believe the answer to this question is: the last one.
Area = length * width
64 = 8 * width
width = 8
Perimeter = 2(Length + Width)
Perimeter = 2(8 + 8)
Perimeter = 2(16)
Perimeter = 32 feet
The perimeter is 32 feet.