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Artyom0805 [142]
3 years ago
6

What is the product? Assume x ≠ 0. 2x^2/3{6/x} 3x 4x 3x2 4x2

Mathematics
2 answers:
Serjik [45]3 years ago
7 0

Answer:

4x

Step-by-step explanation:

The given product is;

\frac{2x^2}{3}(\frac{6}{x})

This is the same as;

\frac{2x^2\times 6}{3\times x}

We cancel out the common factors to obtain;

\frac{2x\times 2}{1\times 1}

Multiply out to obtain;

\frac{4x}{1}

Simplify

4x

The second option is the correct choice.

svlad2 [7]3 years ago
7 0

Answer:

4x

Step-by-step explanation:

\frac{2x^2}{3}(\frac{6}{x})

2x^2 can be written as 2*x*x

so the given expression becomes

\frac{2*x*x}{3}(\frac{6}{x})

we cancel out x at the top and bottom

we know 6 divide by 3 is 2

\frac{2*x}{1}(\frac{2}{1})

Now we multiply the numerator with numerator and denominator with denominator

4x

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Alinara [238K]

Answer:

They are (6, 1) or (3, 2).

Step-by-step explanation:

The factor pairs of 6 are 1×6 and 2×3

So the parallelogram (height by length) could be:

1 by 6

2 by 3

3 by 2

6 by 1.

3 0
3 years ago
APQR is inscribed in a circle with P=60, Q = 80, and R = 40. What are the measures of PQ, QR, and PR?
Sergeeva-Olga [200]

Answer:

PQ:80

QR:160

PR:120

Step-by-step explanation:

PQ=2x∠R

=2×40

=80

QR=2×m∠p

=20×80

=160

PR=2×m∠Q

=2×60\\

=120

<em>hope it helps </em>

<em>have a great day!!</em>

5 0
3 years ago
Explain how to determine whether two known pairs of<br> points are on the same line.
EleoNora [17]
Use the slopeformula 3 times and you should found the pair
3 0
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why are you do such challing things in middle school

Step-by-step explanation:

5 0
3 years ago
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On a 40 question test students gain 6 points for each correct answer and lose 0.5 points on each incorrect answer. If everyone r
juin [17]

Answer:

\text{r}=5.5\text{c}-20

Step-by-step explanation:

GIVEN: On a 40 question test students gain 6 points for each correct answer and lose 0.5 points on each incorrect answer. If everyone required to give an answer to each question.

TO FIND: the formulas that describes how a student's raw score, r, depends on the number of correct answers he or she provided, c.

SOLUTION:

Total number of incorrect questions =40-\text{c}

Total marks deducted due to incorrect question =(40-\text{c})\times0.5=20-0.5\text{c}

Total correct questions =\text{c}

Total marks scored =6\text{c}

Total raw marks \text{r}=\text{total marks gained}-\text{total marks deducted}

                           \text{r}=6\text{c}-(20-0.5\text{c})

                           \text{r}=5.5\text{c}-20

ormulas that describes how a student's raw score, r, depends on the number of correct answers he or she provided, c is  \text{r}=5.5\text{c}-20

7 0
3 years ago
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