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levacccp [35]
3 years ago
12

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! I DONT KNOW HOW TO GRAPH SO CAN YOU SHOW ME HOW TO DO IT PLSSS HELPPPP I WILLL G

IVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLS DRAW IT

Mathematics
2 answers:
SOVA2 [1]3 years ago
8 0

Answer: (-6, 3)

Step-by-step explanation:

svet-max [94.6K]3 years ago
3 0
Y=-6x+3 and you graph it by starting at 3 on the vertical line and then going up 6 boxes and over 1 and keep going up 6 over 1 for the line.
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Help i dont care about the point
Sunny_sXe [5.5K]

Answer:

1.7$

Step-by-step explanation:

Given

original price = $2.87

New price = $2.82

Percentage decrease = original price-New price/New price × 100

Percentage decrease = 2.87-2.82/2.87× 100

Percentage decrease = 0.05/2.87 × 100

Percentage decrease = 5/2.87

Percentage decrease = 1.7%

3 0
3 years ago
You roll a standard number cube 180 times. predict how many times you will roll a 2 or a 3
Gnesinka [82]

Answer:

60 times.

Step-by-step explanation:

Prob( of rolling  a 2) = 1/6

Prob( of rolling  a 3) = 1/6

So Prob( 2 or 3) = 1/6 + 1/6 = 1/3,

So the prediction is 1/3 * 180 = 60.

4 0
2 years ago
2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
What is the surface area of the triangular prism?<br><br> I need answer ASAP
Nezavi [6.7K]

Answer: 81 ft^2

Hello! The surface area of the rectangular prism will follow this process:

Right triangle area: (1/2)bh

So that 6ft (4.5ft) = 27ft^2/2; though when one multiplies that by 2 (as there are two right triangles), we get a surface area of 27ft^2.

For the rectangle's area, it's slightly more deviated since each face is different in length: bh

Face 1 = 3ft(7.5ft) = 22.5ft^2

Face 2 = 3ft(6ft) = 18ft^2

Face 3 = 4.5ft(3ft) = 13.5 ft^2

Thus, if we add these all together (27ft^2. + 22.5ft^2 + 18ft^2 + 13.5 ft^2), we get 81 ft^2

7 0
3 years ago
Give the most convincing explanation you can for why a=c. (Be detailed)<br> please help me
Jlenok [28]

Answer:

a = c because they are vertical angles. vertical angles are alway congruent because they are bascially the same shape. it's a rule.

7 0
4 years ago
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