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DIA [1.3K]
3 years ago
9

Convert 175% to a fraction.

Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 0

Answer:

it will be 175 / 100 = 7 / 4 okay

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You are playing a game using the spinners shown.
Otrada [13]

Answer and Step-by-step explanation:

<u>You should pick Spinner A.</u> There is a high chance of getting red since there are three pieces of the spinner that has red on it, while Spinner B only has 2 instances of red.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

7 0
3 years ago
If f(x) = 5x(3exponent) - 2 and g(x) = 2x+1 , find (f+g) (x)
Rus_ich [418]

For this case we must find

(f + g) (x).

By definition we have to:

(f + g) (x) = f (x) + g (x)

We have the following functions:

f (x) = 5x ^ 3-2\\g (x) = 2x + 1

Now, applying the given definition, we have:

(f + g) (x) = 5x ^ 3-2 + 2x + 1\\(f + g) (x) = 5x ^ 3 + 2x-1

Answer:

(f + g) (x) = 5x ^ 3 + 2x-1

4 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
The following information is obtained from two independent samples selected from two normally distributed populations.
AysviL [449]

A. The point estimate of μ1 − μ2 is calculated using the value of x1 - x2, therefore:

μ1 − μ2 = x1 – x2 = 7.82 – 5.99

μ1 − μ2 = 1.83

 

B. The formula for confidence interval is given as:

Confidence interval = (x1 –x2) ± z σ

where z is a value taken from the standard distribution tables at 99% confidence interval, z = 2.58

and σ is calculated using the formula:

σ = sqrt [(σ1^2 / n1) + (σ2^2 / n2)]

σ = sqrt [(2.35^2 / 18) + (3.17^2 / 15)]

σ = 0.988297

 

Going back to the confidence interval:

Confidence interval = 1.83 ± (2.58) (0.988297)

Confidence interval = 1.83 ± 2.55

Confidence interval = -0.72, 4.38

3 0
3 years ago
WILL GIVE BRAINLIEST - What is the length of the hypotenuse of the base?<br> *Picture linked below*
Citrus2011 [14]

Answer:

4sqrt(2) cm

Step-by-step explanation:

a^2 + b^2 = c^2

4^2 + 4^2 = c^2

32 = c^2

sqrt(32) = c

c = 4sqrt(2)

6 0
2 years ago
Read 2 more answers
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