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Sonja [21]
3 years ago
6

2. Which of the following states of water are described in the passage?

Biology
2 answers:
Jet001 [13]3 years ago
7 0
I think it’s A but we need the passage to see what he has put
kondaur [170]3 years ago
3 0
I hope this helps I think it’s


A liquid,gas, and ice
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Different plant species require different amounts of direct sunlight in order to flower. A student designed an experiment to det
Gnoma [55]

Answer:

Independent variable: LENGTH OF EXPOSURE TO DIRECT SUNLIGHT

Dependent variable: PRODUCTION OF FLOWERS

Control group: THE GROUP OF PLANT THAT WASN'T EXPOSED TO SUNLIGHT i.e. 0 hours

Experimental group: THE GROUP OF PLANTS THAT WERE EXPOSED TO SUNLIGHT

Constant: THE SAME PLANT SPECIES

Explanation:

Independent variable is the variable that the experimenter changes or manipulates in an experiment. In this experiment, the experimenter exposes the specific plant species to sunlight at different length of time, hence, the LENGTH OF EXPOSURE TO DIRECT SUNLIGHT is the independent variable.

Dependent variable is the variable which is measured in an experiment. In this experiment, the measured/dependent variable is the PRODUCTION RATE OF FLOWERS by the plant species.

Control group is the group in an experiment that does not receive the variable being tested. In this experience, the control group is THE GROUP OF PLANT THAT WASN'T EXPOSED TO SUNLIGHT i.e. 0 hours

Experimental group is the group of am experiment that is exposed to the experimental treatment (sunlight). In this case, the experimental group is THE GROUP OF PLANTS THAT WERE EXPOSED TO SUNLIGHT.

Constants are variables of an experiment that must be kept unchanged for all groups throughout the experiment in order not to affect the experiment's outcome. In this experiment, the constant is THE SAME PLANT SPECIES used,

3 0
3 years ago
Select the correct answer.
andrew-mc [135]

Answer:

precipitation is when it rains. it occurs last

Explanation:

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Which of the following types of nonrenewable fuel sources requires the storage of radioactive waste?
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Answer: D. nuclear

Explanation:

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Mitigating the risk of cytokine release syndrome in a Phase I trial of CD20/CD3 bispecific antibody mosunetuzumab in NHL: impact
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Mosunetuzumab is a T-cell reliant bispecific antibody that binds to CD3 and CD20 to trigger T-cell mediated B-cell death.

However, cytokine release syndrome, which has the potential to limit dose and efficacy, can result from powerful immune stimulation with T-cell focused treatments.

We created a novel mechanistic model of immune and antitumor responses to the T-cell bispecifics (mosunetuzumab and blinatumomab), taking into account the dynamics of B- and T-lymphocytes in circulation, lymphoid tissues, and tumors, in order to better understand the mechanisms underlying safety and efficacy as well as to explore safety mitigation strategies.

Using mosunetuzumab nonclinical and blinatumomab clinical data, the model was created and validated. The initial step-fractionated dose was projected to minimize systemic T-cell activation and cytokine release without impairing tumour response.

Simulations described the mechanisms underlying the observed cell and cytokine (IL6) dynamics. The Phase I clinical study for mosunetuzumab was changed to a step-fractionated treatment schedule as a result of these findings, allowing for the safer administration of greater dosages.

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7 0
2 years ago
Glycolysis is a metabolic pathway that converts glucose into pyruvate and is observed in each of the three domains. The hexokina
Trava [24]

Answer:

Plant cells will be unable to perform glycolysis due to the inhibitor and will die.

Explanation:

Glucose is  a high energy stable compound.Therefore in order to extract the stored energy for cellular use, it must be broken down. The addition of inorganic Phosphate ions(Pi) to 6-carbon glucose compound in the presence of 2ATP  molecules is called Phosphorylation. This phosphorylation  reaction is catalyse by Hexokinase.

The 6C-glucose is spitted to  6C-Fructose phosphate, and  to 6C-fructose biphophate. The later is converted to 2molecules of 3Carbon compounds called triose phosphate.

It is during the  conversion of 2-molecules of 3C- triphosphate  to Pyruvate  that yields 2 ATPs per molecule of glucose.

Therefore if  hexokinase is inhibited ,  then the glucose phosphorylation can not occur. Hence the sequence of events as Glycolytic pathways that leads to  production of ATP during   formation of Pyruvate can not occur.

Definitely, plant cells biochemical reactions will seize, glycolytic pathways will  be inhibited,  ATPs will not be synthesized,leading to plant cells  deaths.

7 0
3 years ago
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