<span>Studying the changes in densities of pocket gophers when large herbivores such as elk are excluded from mountain forests would be an example of studying ecology at the community level.
A community refers to a group of organisms of various species that live in the same location and interact with each other. So, if this scientist is observing gophers and elks, they are looking at the level of communities, not anything more or less.
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Answer:
CFU/mL
Explanation:
Given -
a) Number of colonies of bacteria is equal to 
b) Total volume of the solution is equal to
mL
c) Dilution factor is equal to 
As we know that
CFU/mL 
Where N is the number of bacterial colonies, DF is the dilution factor and V is the volume
Substituting the given values in above equation, we get -
CFU/mL 
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Answer:
Because Venus and Mercury are closer to the sun they are never visible at around midnight
Explanation:
I've read about this in articles
Answer:
(A). Result in different amino acids to be read due to frame shifts
Explanation:
Insertion or deletion mutations (or Indel mutations) can be defined as mutations in DNA due to insertion (addition) or deletion of nucleotide bases in DNA.
These mutations lead to change in reading frames (sequence of codons), which leads to formation of protein having completely different amino acid sequence. Hence, these mutations are also cause frameshift mutations.
This is due due to triplet nature of genetic codes as insertion or deletion of one or more bases (but not three) would change change in codon sequence and mutated sequence can form a non-functional or truncated protein.
Thus, the correct answer is option (A).