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zmey [24]
3 years ago
11

Homework, pls help ( 10 points )

Mathematics
1 answer:
NeTakaya3 years ago
4 0
4(8x + 3y)

= 32x + 12y
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What are the coordinates of point A?<br> (–2, –6)<br> (–6, –2)<br> (–6, –3)<br> (–3, –6)
AlekseyPX
(-3,-6) is the answer
3 0
3 years ago
What is 25 miles/hours equal to feet/seconds
taurus [48]
1 mile/hour = 5280 feet/(60 x 60) seconds = 1.467 feet/second

25 miles/hour = 1.467 x 25 = 36.67 feet/second.
7 0
3 years ago
Can someone please help me? Thanks
Daniel [21]

Answer:

693 sq. m.

Step-by-step explanation:

The figure consists of a triangular prism (Bottom Part) and a Triangular Pyramid (Top Part). We will find the volume of each and add it up to get volume of total figure.

1. Volume of Triangular Prism = Area of Triangular Base * Height

Area of Triangular Base = (1/2)*base*height

Given that the triangle is a right triangle, we find the unknown side by using Pythagorean Theorem, which tells us:

Leg^2 + Another Leg^2 = Hypotenuse^2

8.8^2 + Another Leg^2 = 13.7^2

77.44+ Another Leg^2 = 187.69

Another Leg (unknown side, or the base of the triangle) = Sqrt(187.69-77.44) = 10.5 (this is base of triangle)

So, we have:

Area of Triangular Base = \frac{1}{2}*10.5*8.8=46.2

Thus,

Volume of Triangular Prism = 46.2 * 10(given) = 462 sq.m.

2. Volume of Triangular Pyramid = (1/3) * area of triangular base * height

Here, area of triangular pyramid is 46.2 (already found)

the height of the pyramid is 25 - 10 = 15

SO, we have:

Volume of Triangular Pyramid = \frac{1}{3}*46.2*15=231 sq. m.

Now we sum them up and get total volume of the figure:

Total Volume of Figure = 462+ 231 = 693 sq. m.

6 0
3 years ago
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
ANEK [815]

Answer:

\frac{360000q}{359999}

Step-by-step explanation:

p = Product of all odd integers between 500 an 598. So,

p = 501 x 503 x 505 ... x 595 x 597

q = Product of all odd integers between 500 and 602. So,

q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601

From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.

q = p x 599 x 601

or,

p=\frac{q}{599 \times 601}

We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:

p+q=\frac{q}{599 \times 601} + q\\\\ p+q=\frac{q+(599 \times 601q)}{599 \times 601}\\ \\ p+q=\frac{q(1+599\times601)}{599 \times 601}\\\\ p+q=\frac{360000q}{359999}

7 0
3 years ago
Rewrite the following equation in logarithmic form and exponential form
Slav-nsk [51]

Answer:The answer for the first one is log2(.25)=-2

The answer for the second one is 8^3=512

Step-by-step explanation:

7 0
3 years ago
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