To get the largest area, the length and the width have to be as close as possible, if not the same.
Given Perimeter = 176 unit.
Length = 176 ÷ 4 = 44 units
Area = Length x Width
Area = 44 x 44 = 1936 units²
1936 units² is the largest possible area, given that the perimeter is 176 units. The dimension being 44 by 44
Perimiter=legnth+legnth+width+width=2lengt+2width
lesngh=60
perimiter=60+60+2width
perimiter=120+2widht
222=120+2width
subtract 120 from both sdies
102=2width
divide by 2
51 mm=width
X=6 2+1=3 and 3 x 2=6 so x is 6
To find the shaded area in an image first calculate the total area of the figure and then subtract the white area from this total.
<h3>How to find the area of a shaded area?</h3>
- Determine the total area of the figure, in this case, the are of the rectangle that contains the triangle and the semicircle.
- Calculate the area of the white region.
- Substract the non-shaded area to the total area.
<h3>How to find out the area of different shapes?</h3>
- Rectangle: side x side = 2 x 4 = 8 square feet
- Isosceles triangle = 1/2 base x height
- Semicirle = 1/2 (π x r^2)
Note: This question is incomplete because the image of the shaded regions is not provided; due to this, the answer is based on general knowledge.
Learn more about triangles in: brainly.com/question/2773823
All factors of 12 are {-12, -6, -4, -3, -2, -1, 1, 2, 3, 4, 6, 12}, so x is one of these numbers.
t is a prime, so t∈{2, 3, 5, 7, 11, 13, 17, 19, 23....}
A) t/x cannot be 1/12, because 1 is not a prime. NOT POSSIBLE
B) 1/4 = 3/12 ...... 3 is a prime and 12 is a factor of 12. POSSIBLE
C) 1/2= 3/6 .....3 is a prime and 6 is a factor of 12. POSSIBLE
D) 1 = 2/2....... 2 is a prime and 2 is a factor of 12. POSSIBLE
E) 2 = 2/1 ....... 2 is a prime and 1 is a factor of 12. POSSIBLE
Answer: A
