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EleoNora [17]
3 years ago
10

(5h​3​​−8h)+(−2h​3​​−h​2​​−2h)

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0
(5h^3-8h)+(-2h^3-h^2-2h)

First, you would distribute into parentheses but there is nothing

5h^3-8h-2h^3-h^2-2h

Now, separate all into common terms

(5h^3-2h^3)(h^2)(-8h-2h)

Now simplify

3h^3h^2-10h
PSYCHO15rus [73]3 years ago
3 0
<span>(5h^​3 ​​− 8h) + (−2h​^3 ​− h^​2 ​​− 2h)
= 5h^3 - 8h - 2h^3 - h^2 - 2h
= 3h^3 - h^2 - 10h</span>
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<u>Answer-</u>

\boxed{\boxed{f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0}}

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Here, n represents the number of months and f(n) represents the number of laptops in the store after n months.

As the store had 150 laptops in the month of January or at the beginning.

So f(0)=150

Every month, 20% of the laptops were sold and 10 new laptops were stocked in the store.

As 20% of laptops were sold, so 80% were in the store.

So, after one month total number of laptops in the store,

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Again after one month total number of laptops in the store,

\Rightarrow f(2)=0.8\times (0.8(150)+10)+10

\Rightarrow f(2)=0.8(f(1))+10     (\because f(1)=0.8(150)+10)

Analyzing the pattern, the recursive function f(n) will be,

f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0


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