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EleoNora [17]
3 years ago
10

(5h​3​​−8h)+(−2h​3​​−h​2​​−2h)

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0
(5h^3-8h)+(-2h^3-h^2-2h)

First, you would distribute into parentheses but there is nothing

5h^3-8h-2h^3-h^2-2h

Now, separate all into common terms

(5h^3-2h^3)(h^2)(-8h-2h)

Now simplify

3h^3h^2-10h
PSYCHO15rus [73]3 years ago
3 0
<span>(5h^​3 ​​− 8h) + (−2h​^3 ​− h^​2 ​​− 2h)
= 5h^3 - 8h - 2h^3 - h^2 - 2h
= 3h^3 - h^2 - 10h</span>
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A toy box has a volume of 1/3 cubic yard.What is the volume of the toy box
artcher [175]
1/2 and that will be your answer
3 0
3 years ago
I need help with this, anyone nice enough to help? :’)
kirza4 [7]

Answer:

7m³ - 11m² + 5m + 17

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Distributive Property

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

3m³ - 4m² + 8 - (-4m³ + 7m² - 5m - 9)

<u>Step 2: Simplify</u>

  1. [Distributive Property] Distribute negative:                                                  3m³ - 4m² + 8 + 4m³ - 7m² + 5m + 9
  2. Combine like terms (m³):                                                                                7m³ - 4m² + 8 - 7m² + 5m + 9
  3. Combine like terms (m²):                                                                                7m³ - 11m² + 8 + 5m + 9
  4. Combine like terms (Z):                                                                                   7m³ - 11m² + 5m + 17
3 0
3 years ago
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stiv31 [10]
#22

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3 years ago
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Scientists discover two planets orbiting a distant star. The average distance from the star to Planet A is 4 AU, and it takes 43
Kitty [74]

Answer:

Option C - 9 AU

Step-by-step explanation:

To find : What is the average distance from Planet B to the star?

Solution :

According to kepler's law,

The squares of the sidereal periods (of revolution) of the planets are directly proportional to the cubes of their mean distances from the Sun.

i.e. P^2\propto S^3

We have given,

The average distance from the star to Planet A is S_1=4 AU.

It takes 432 Earth days for Planet A to orbit the star i.e. P_1=432

It takes 1,460 days for Planet B to complete an orbit i.e.  P_2=1460

Substitute the values in (\frac{P_1}{P_2})^2=(\frac{S_1}{S_2})^3

(\frac{432}{1460})^2=(\frac{4}{S_2})^3

0.0875=(\frac{4}{S_2})^3

Taking root cube both side,

\sqrt[3]{0.0875}=\frac{4}{S_2}

0.444=\frac{4}{S_2}

S_2=\frac{4}{0.444}

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The average distance from Planet B to the star is 9 AU.

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5 0
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