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Aleks [24]
3 years ago
13

How many Oxygen atoms are in the Fertilizer, Ca(H2PO4)2?

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
4 0

Answer:

234.052482 g/mol

Explanation:

Molecular weight calculation:

40.078 + (1.00794*2 + 30.973761 + 15.9994*4)*2

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Calculate the man’s height . (Use PE = m × g × h, where g = 9.8 N/kg.)
monitta
From the formula PE = mgh, find h.

Divide both sides for mg (because we have them) so we have PE/mg = mgh/mg

h = PE/mg

h = 4620 J/ (56 kg * 9,8 N/kg)

h = 4620 J / 548.8 N = 8.4 m (circa)
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3 years ago
The ph of lemon juice is approximately 2.4. at this ph, the hydronium ion concentration is closest to which value? 1. 250 m 2. 4
babymother [125]

Answer is: concentration of hydrogen cations in lemon juice is 4.00 × 10−3 m.

pH = 2.4.

pH = -log[H₃O+].

[H₃O+] = 10∧(-pH).

[H₃O+] = 10∧(-2.4).

[H₃O+] = 0.004 mol/L.

pH value (potential of hydrogen - [H+]) is a logarithmic scale that specify the acidity or basicity of an aqueous solution. When pH is greater than seven, aqueous solution is basic, below seven is acidic and when pH is equal seven, solution is neutral.
8 0
3 years ago
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Electrons always fill orbitals in the same order. Each s orbital holds 2 electrons, each set of p orbitals holds 6 electrons, ea
arsen [322]
Oxygen is the answer :)

4 0
3 years ago
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If 13.7 grams of manganese oxide reacts with excess hydrogen chloride gas, how many grams of water are formed?
Lerok [7]

Answer:

5.67 g OF WATER WILL BE FORMED WHEN 13.7 g OF MnO2 REACTS WITH HCl GAS.

Explanation:

EQUATION FOR THE REACTION

Mn02 + 4HCl --------> MnCl2 + Cl2 + 2H2O

From the balanced reaction between manganese oxide and hydrogen chloride gas;

1 mole of MnO2 reacts to form 2 mole of water

At STP, the molecular mass of the sample is equal to the mole of the substance. So therefore:

(55 + 16 * 2) g of MnO2 reacts to form 2 * ( 1 *2 + 16) g of water

(55 + 32) g of MnO2 reacts to form 2 * 18 g of water

87 g of MnO2 reacts to form 36 g of water

If 13.7 g of MnO2 were to be used?

87 g of MnO2 = 36 g of H2O

13.7 g of MnO2 = ( 13.7 * 36 / 87) g of water

= 493.2 / 87 g of water

Mass of water = 5.669 g of water

Approximately 5.67 g of water will be formed when 13.7 g of manganese oxide reacts with excess hydrogen chloride gas.

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Answer:

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