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Assoli18 [71]
4 years ago
12

Why is creation ex nihilo a religious belief and not a scientific fact

Chemistry
2 answers:
Tasya [4]4 years ago
5 0

I googled it but it just says some weird stuff about it being a latin phrase but you could of just searched that one up

Readme [11.4K]4 years ago
4 0

What now? I don't get it.

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CO2 <br><br> element <br><br><br> number x Atomic mass =total mass
MaRussiya [10]

Answer:

Number= 6

Atomic mass= 12,01115

Explanation:

4 0
3 years ago
1. Find the molar mass of the compounds<br>a. K2Cro4​
Luda [366]

Answer:

194.1903

Explanation:

that is for one mole of K2Cro4

8 0
3 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°
miskamm [114]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1835 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)    \Delta H_1=157kJ   ( × 4)

(2) P_4(g)+6Cl_2(g)\rightarrow 4PCl_3(g)     \Delta H_2=-1207kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[4\times (-\Delta H_1)]+[1\times \Delta H_2]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-157))+(1\times (-1207))=-1835kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1835 kJ.

6 0
3 years ago
Which model was proposed as a result of Rutherford's scattering experiment where positive particles did not pass straight throug
dimulka [17.4K]

Answer:

the nuclear model of the atom

6 0
2 years ago
How much heat is absorbed/released when 25.00 g of NH3(g) reacts in the presence of excess O2(g) to produce NO(g) and H2O(l) acc
Novay_Z [31]

Answer:

429.4 kJ are absorbed in the endothermic reaction.

Explanation:

The balanced chemical equation tells us that 1168 kJ of heat are absorbed in the reaction when 4 mol of NH₃ (g) react with 5 mol O₂ (g).

So what we need is to calculates how many moles represent 25 g NH₃(g) and calculate the heat absorbed. (NH₃ is the limiting reagent)

Molar Mass NH₃  = 17.03 g/mol

mol NH₃ = 25.00 g/ 17.03 g/mol = 1.47 mol

1168 kJ /4 mol NH₃  x 1.47 mol  NH₃ =  429.4 kJ

6 0
3 years ago
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