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ad-work [718]
3 years ago
9

Indicate the number of unpaired electrons for following: [noble gas]ns2np5

Chemistry
1 answer:
Fantom [35]3 years ago
4 0
1 unpaired electron. 
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Which statement correctly describes a covalent bond?  The valence electrons are joined in a shell around the atoms. The valence
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The valence electrons are shared between the atoms
4 0
3 years ago
Consider the balanced equation below.
Alexus [3.1K]

Answer : The mole ratios of Hydrazine to Hydrogen peroxide is 1 : 2 and

                the mole ratios of Hydrazine to water is 1 : 4.

Explanation :

The balanced chemical equation is,

N_{2}H_{4}+2H_{2}O_{2}\rightarrow N_{2}+4H_{2}O

According to the given reaction,

1 mole of Hydrazine react with the 2 moles of Hydrogen peroxide.

Therefore, the mole ratios of Hydrazine to Hydrogen peroxide is 1 : 2

And in case of Hydrazine and water,

1 mole of Hydrazine gives 4 moles of water.

Therefore, the mole ratios of Hydrazine to water is 1 : 4

5 0
3 years ago
Read 2 more answers
Help me plzz in chemistry​
AlexFokin [52]

a) f2 loses electrons and is oxidised. li gains electrons and is reduced

c)sn2+ loses electrons and is oxidised.Al gains electrons and is reduced

b)br2 loses electrons and is oxidised. I- in KI gains electrons and is reduced

5 0
3 years ago
2. The approximate concentration of hydrochloric acid, HCl, in the stomach (stomach
Sergio039 [100]

Answer:

a) 0.714g of bicarbonate of soda are required.

b) 0.221g of Al(OH)₃ are required

Explanation:

The reactions of HCl with bicarbonate of soda and aluminium hydroxide are:

HCl + NaHCO₃ → H₂O + NaCl + CO₂

3 HCl + Al(OH)₃ → 3H₂O + AlCl₃

The moles of HCl that we need neutralize are:

50mL = 0.050L * (0.17mol / L) = 0.0085 moles HCl

To solve these problem we need to find the moles of the antacid using the chemical reaction and its mass using its molar mass;

<em>a) </em><em>Moles NaHCO₃ = Moles HCl = 0.0085 moles </em>

The mass is -Molar mass NaHCO₃: -84g/mol-

0.0085 moles * (84g / mol) = 0.714g of bicarbonate of soda are required

b) 0.0085 moles HCl * (1mol Al(OH)₃ / 3mol HCl) = 2.83x10⁻³ moles Al(OH)₃

The mass is -Molar mass: 78g/mol-:

2.83x10⁻³ moles Al(OH)₃ * (78g/mol) =

<h3>0.221g of Al(OH)₃ are required</h3>
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2 years ago
Use the dropdown to create a unbalanced diagram with the dog using Applied Force pulling to the right.
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Is there an image with this question
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