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Serjik [45]
3 years ago
15

Determine the solution for the system of equations below.

Mathematics
1 answer:
NeX [460]3 years ago
8 0

Answer:

(0,0)

Step-by-step explanation:

4x + 4x = 0

 8x = 0

8x / 8 = 0 / 8

 x = 0

y = 4x

y = 4(0)

y = 0

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For what values of x is x + 2x = 24 true?
sveta [45]
I’m sorry. But none of your choices are correct. The correct answer would be 3 and 4. Further more explaining= 3+ 2 times 4 is 24. 2x= 4. That equals 8 and 3 times 8 is 24
5 0
3 years ago
Answer choices are <br> y-x=-4<br> y-x=-2<br> y-4=x<br> y+4x=1
ycow [4]

Answer:

Y+4x=1

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Factor the polynomial: <br> x^2 + 5x − 14 = <br> x^2 − 10x + 16 =
Nastasia [14]
The first one is x square +5x-4
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8 0
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Show that if x and y may both be written as the sum of the squares of two rational integers, then their product xy may also be w
Georgia [21]

Answer:

See proof below

Step-by-step explanation:

One way to solve this problem is to "add a zero" to complete the required squares in the expression of xy.

Let x=m^2+n^2 and y=l^2+k^2 with m,n,l,k\in \mathbb{Z}. Multiplying the two equations with the distributive law and reordering the result with the commutative law, we get xy=(m^2+n^2)(l^2+k^2)=m^2l^2+m^2k^2+n^2l^2+n^2k^2=n^2l^2+m^2k^2+m^2l^2+n^2k^2

Now, note that 0=2lkmn-2lkmn=2nkml-2nlmk by the commutativity of rational integers. Add this convenient zero the the previous equation to obtain xy=n^2l^2-2nlmk+m^2k^2+m^2l^2+2nkml+n^2k^2=(nl-mk)^2+(ml+nk)^2, thus xy is the sum of the squares of nl-mk,ml+nk\in \mathbb{Z}.

7 0
2 years ago
19-11+(-17)+(-19)+11?
yulyashka [42]

-17

hope i helpedddd :)

6 0
3 years ago
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