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shepuryov [24]
3 years ago
15

Find the area of this figure 15ft 10ft 10ft 5

Mathematics
1 answer:
miskamm [114]3 years ago
7 0

Answer:

150 feet2 50 feet I hope this helps!

Step-by-step explanation:

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The ratio of boys to girls in a class is 7:5. There are 36 students in the class. How many
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There are 15 girls and 21 boys

Step-by-step explanation:

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What is the queuing theory and how to use it?
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As a branch of operations research, queuing theory can help inform business decisions on how to build more efficient and cost-effective workflow systems. Queuing theory is the study of the movement of people, objects, or information through a line.

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A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
marta [7]

Answer:

(a) The probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b) <em>n</em> = 28.09

Step-by-step explanation:

The random variable <em>Y</em>ₙ is defined as the total numbers of dollars paid in <em>n</em> years.

It is provided that <em>Y</em>ₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of <em>Y</em>ₙ are:

\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}

(a)

For <em>n</em> = 20 the mean and standard deviation of <em>Y</em>₂₀ are:

\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\

Compute the probability that <em>Y</em>₂₀ exceeds 1000 as follows:

P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z>  4.47)\\=1-P(Z

**Use a <em>z </em>table for probability.

Thus, the probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b)

It is provided that P (<em>Y</em>ₙ > 1000) > 0.99.

P(Y_{n}>1000)=0.99\\1-P(Y_{n}

The value of <em>z</em> for which P (Z < z) = 0.01 is 2.33.

Compute the value of <em>n</em> as follows:

z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n}  \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0

The last equation is a quadratic equation.

The roots of a quadratic equation are:

n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of <em>n</em> = 28.09.

8 0
3 years ago
Solve.<br><br> Round to the nearest hundredth.<br><br> 29.3 = 1.7y
Elena-2011 [213]

Steps to Solve:

29.3 = 1.7y

29.3/1.7 = 1.7y/1.7

y = 17.2352941176

In this case, we round up the hundredths place because the number in the thousandths place is 5 or higher.

y = 17.24

Hope this helps!! :)

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For which intervals the graphs of the functions f(x) = x^3 + x^2 - 4x - 4 is positive
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Step-by-step explanation:

Consider a function

f

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x

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5 0
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