Rime factorization of 2001:
By prime factorization of 2001 we follow 5 simple steps:
1. We write number 2001 above a 2-column table
2. We divide 2001 by the smallest possible prime factor
3. We write down on the left side of the table the prime factor and next number to factorize on the ride side
4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)
5. We continue until we reach 1 on the ride side of the table
<span>2001<span>prime factorsnumber to factorize</span><span>3667</span><span>2329</span><span>291</span></span>
<span>Prime factorization of 2001 = 1×3×23×29= </span><span>1 × 3 × 23 × 29</span>
Answer:
-68.6
Step-by-step explanation:
subtracting a negative from a negative is addition.
We have that
[√(2x+1)]+3=0
for x=4
[√(2*4+1)]+3=0
[√(9)]+3=0
3+3=0----------6 is not zero
therefore
the solution is not correct for x=4
[√(2x+1)]+3=0--------> [√(2x+1)]=-3---------> <span>There is no real solution for that equation
</span>Because (2x+1) >= 0
the solution is with complex numbers
Answer:
The answer is C
Step-by-step explanation:
The roots are −1.87938524, 0.34729635, 1.53208888, −1.87938524, 0.34729635, and 1.53208888. That's 6 roots, which is C.
