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3 years ago

What’s this pls help me !!!!!

Mathematics

2 answers:

leonid [27]3 years ago

6 0

the answer is 12-2x

DIA [1.3K]3 years ago

4 0

Step-by-step explanation:

hope it's helpful ❤❤❤❤

THANK YOU

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Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec

expeople1 [14]

Answer:

$cot x = \frac{cos x}{sin x}$

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

$cos x cot x + sin x$

We know from math properties that the definition for cot is $cot x = \frac{cos x}{sin x}$

If we use this definition we got:

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

Now we can use the following identity:

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

4 0

3 years ago

P-please help (30 points)

liubo4ka [24]

Answer:

No .1

Ans ; 2

No.2

Ans ; 3

Step-by-step explanation:

Multiply or add and if the value is whole no. then its W else L

8 0

2 years ago

Alenkasestr [34]

All four choices are correct responses to the question.

7 0

3 years ago

Read 2 more answers

26 = 3x - 2 - 7x show york work but please try to summarize you're explanation

Delvig [45]

26 = 3x - 2 - 7x
26 + 2 = -4x
28 / -4 = x
x = -7
Best answer me please!

6 0

3 years ago

(PLS HELP AND FAST )The edges of three squares are joined together to form a right triangle with legs of lengths /

Elena-2011 [213]

Answer:

R^{2} + S^{2} = T^{2}

Step-by-step explanation:

the pythagorean theorem

4 0

2 years ago