I believe the answer is: A fly eats a piece of fruit;
From all organism on earth, those who obtain their food through photosynthesis are the one that contain the largest amount of energy, and the energy transferred would keep getting smaller as the organism being consumed by other organism. From the sample above, only trees where the fruit is hanging are the one that obtain their food through photosynthesis
Answer:
True
Explanation:
The legislative branch is the part of the United States government that creates laws. Whenever you read about congresspeople in the Senate or House debating a law, you're reading about the legislative branch: the branch of the government that writes, debates, and passes laws.
The thing that convinces scientists that current warming trends are not solely part of Earth's natural cycle is B. The current changes are happening much faster than past changes.
<h3>Who is a scientist?</h3>
It should be noted that a scientist simply means someone who studied science and researches in science.
In this case, the thing that convinces scientists that current warming trends are not solely part of Earth's natural cycle is that the current changes are happening much faster than past changes.
In conclusion, the correct option is B.
Learn more about scientist on:
brainly.com/question/458058
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Answer:
2.84*10^-3 years = 0.00284*10^-3 years
Explanation:
To find the orbital period you use the following formula:
![T=\sqrt{\frac{4\pi^2r^3}{GM}}](https://tex.z-dn.net/?f=T%3D%5Csqrt%7B%5Cfrac%7B4%5Cpi%5E2r%5E3%7D%7BGM%7D%7D)
r: 2.0A = 2.0(1.5*10^11m)=3*10^11 m
G: Cavendish constant = 6.67*10^-11 Nm^2/kg^2
M: mass of the sun = 1.98*10^30 kg
![T=\sqrt{\frac{4\pi^2(3*10^{11}m)^3}{(6.67*10^{-11}Nm^2/kg^2)(1.98*10^{30}kg)}}\\\\T=89839.27\ s](https://tex.z-dn.net/?f=T%3D%5Csqrt%7B%5Cfrac%7B4%5Cpi%5E2%283%2A10%5E%7B11%7Dm%29%5E3%7D%7B%286.67%2A10%5E%7B-11%7DNm%5E2%2Fkg%5E2%29%281.98%2A10%5E%7B30%7Dkg%29%7D%7D%5C%5C%5C%5CT%3D89839.27%5C%20s)
Next, you calculate the time in seconds of one Earth's year:
![1\ year=365days*\frac{24\ h}{1\ day}*\frac{3600\ s}{1\ h}=31536000\ s](https://tex.z-dn.net/?f=1%5C%20year%3D365days%2A%5Cfrac%7B24%5C%20h%7D%7B1%5C%20day%7D%2A%5Cfrac%7B3600%5C%20s%7D%7B1%5C%20h%7D%3D31536000%5C%20s)
thus, you use this value to find the orbital period of the asteroid in Earth's year:
![T=89839.27\ s*\frac{1\ year}{31536000\ s}=2.84*10^{-3}\ years](https://tex.z-dn.net/?f=T%3D89839.27%5C%20s%2A%5Cfrac%7B1%5C%20year%7D%7B31536000%5C%20s%7D%3D2.84%2A10%5E%7B-3%7D%5C%20years)