Answer: 24.52%
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Work Shown:
Convert the time 7:45, which represents 7 min 45 sec, to seconds only
7:45 = (7 min) + (45 sec)
7:45 = (7*60 sec) + (45 sec)
7:45 = (420 sec) + (45 sec)
7:45 = (420+45) sec
7:45 = 465 sec
Do the same for 5:51
5:51 = (5 min) + (51 sec)
5:51 = (5*60 sec) + (51 sec)
5:51 = (300 sec) + (51 sec)
5:51 = (300+51) sec
5:51 = 351 sec
So the initial time is 465 seconds and it drops to 351 seconds
Subtract the values to find the amount dropped: 465-351 = 114
Divide that difference over the initial time: 114/465 = 0.24516
Move the decimal over 2 spots to the right to convert to a percentage: 0.24516 --> 24.516%
Then round to the nearest hundredth of a percent (2 decimal places) to go from 24.516% to 24.52% which is our final answer
So the reduction is roughly 24.52%
This means if you took 24.52% of the initial time and subtracted it off, then you'd get to about 351 seconds.
Answer:
128/7 or 18 2/7
Step-by-step explanation:
the decimal answer is 18.28571428... so if you round it, it is 18.3
Step-by-step explanation:
First of all we need to know the formula for the circumference which is: 
We don't have the radius. What we only have is the area; therefore, we must use the area formula and extract the radius from it.
The formula for the area is: 
Solve for r;
![r^2=\frac{A}{\pi}\\ r=\sqrt[]{\frac{A}{\pi} }](https://tex.z-dn.net/?f=r%5E2%3D%5Cfrac%7BA%7D%7B%5Cpi%7D%5C%5C%20r%3D%5Csqrt%5B%5D%7B%5Cfrac%7BA%7D%7B%5Cpi%7D%20%7D)
![r=\sqrt[]{\frac{50.24inch^2}{3.14} }](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B%5D%7B%5Cfrac%7B50.24inch%5E2%7D%7B3.14%7D%20%7D)
![r=\sqrt[]{16inch^2}\\ r=4inch](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B%5D%7B16inch%5E2%7D%5C%5C%20r%3D4inch)
Now that we've found the radius, we simply plug it into the circumference formula.
Answer:i don,t have the answer but i can tell you this with volume you have to do length times width times height
Step-by-step explanation:
sorry that i don,t have the answer that you were hoping for
Answer:
Step-by-step explanation:
That's just about impossible to determine...
