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padilas [110]
3 years ago
11

Find the percentage of the following:20/6018/6021/6031/60​

Mathematics
2 answers:
Artemon [7]3 years ago
7 0

Answer:

  1. 20/60 = 33%
  2. 18/60 = 30%
  3. 21/60 = 35%
  4. 31/60 = 51.67%

I hope th is helps you I just divided the fractions by the way :)

dangina [55]3 years ago
6 0

Answer:

20/60 = 33%

18/60 = 30%

21/60 = 35%

31/60 = 52%

Step-by-step explanation:

Just divide em'

Simple as that.

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A stadium holds 50,000 people.The stadium is divided into 250 different seating sections.How many seats are in each section?
worty [1.4K]
50,000 ÷ 250 = 200

This means that there are 200 seats in each section.
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What is the solution to the system of equations? Use the substitution method. {y=2x+43x−6y=3
garri49 [273]
We have that
<span>y=2x+4--------> equation 1
3x−6y=3-------> equation 2

step 1
</span>I substitute the value of y in equation 1 for the value of y in equation 2<span>
so
</span>3x−6*[2x+4]=3-------> 3x-12x-24=3
-9x=3+24
-9x=27------> 9x=-27
x=-27/9
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step 2
<span>I substitute the value of x in equation 1 to get the value of y</span>
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3 years ago
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Below are three different hypothesis tests about population proportions. For each test, use StatKey and the information given to
Ilia_Sergeevich [38]

Answer:

1a) p-hat=0.38

1b) P=0.08

1c) The null hypothesis is not rejected

2a) p-hat=0.64

2b) P=0.0027

2c) The null hypothesis is rejected

3a) p-hat=0.55

3b) P=0.153

3c) The null hypothesis is not rejected

Step-by-step explanation:

(1) H0: p = 0.3 vs Ha: p ≠ 0.3. In their survey, they had a count of 38 using a sample size n=100.

1a) The p-hat is p-hat=38/100=0.38.

1b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.3*0.7}{100}}=0.046

The sample size is n=100.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.38-0.3}{0.046}=\frac{0.08}{0.046}= 1.74

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.74 is P=0.08.

1c) The null hypothesis is not rejected.

(2) H0: p = 0.7 vs Ha: p ≠ 0.7. In their survey, they had a count of 320 using a sample size n=500.

2a) The p-hat is p-hat=320/500=0.64.

2b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7*0.3}{500}}=0.02

The sample size is n=500.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.64-0.7}{0.02}=\frac{-0.06}{0.02}=-3

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=3 is P=0.0027.

2c) The null hypothesis is rejected.

(3) H0: p = 0.6 vs Ha: p < 0.6. In their survey, they had a count of 110 using a sample size n=200.

2a) The p-hat is p-hat=110/200=0.55.

2b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.6*0.4}{200}}=0.035

The sample size is n=200.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.55-0.6}{0.035}=\frac{-0.05}{0.035}=-1.43

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.43 is P=0.153.

2c) The null hypothesis is not rejected.

8 0
3 years ago
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