<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 
Answer:
Its 1.75
Step-by-step explanation:
hes going 0.25 faster every meet
You need to find the least common denominator first which is 4. 3 3/4 can stay the same but you must have like denominators to add so change 1 1/2 to 1 2/4 by multiplying by 2/2. You know have like denominators and you can add whole numbers first 3+1=4 and then the fractions 3/4+2/4= 5/4 which is also 1 1/4. Now you add 4 so your answer is 5 1/4