I believed you are looking for the value of e. The value of e is 16 below is the solution:
A×4 = E, so A=E/4
B/4 = E, so B=4E
C+4 = E, so C=E=4
D-4 = E, so D=E+4
and
A+B+C+D=100.
Substitute values of A, B, C and D in the equation, we get,
(E/4) + 4E + E-4 + E+4 = 100
(E/4) + 4E + 2E = 100
(E/4) + 6E = 100
(E+24E)/4 = 100
E+24E = 100×4
25E = 400
E = 400/25
<span>E = 16</span>
k=2
Step-by-step explanation:
since all the base are 10 you use the powers to solve it.
so it would be -3+1+k=-3=-3
All 12 months have 28 days in it.
because every month has 28 days ( February) or more number of days like the other months(Jan, Mar..)
Answer:
The randomization distribution is created under the assumption that H₀: p = 0.1
The randomization distribution will also be centred at 0.1
Step-by-step explanation:
If the distribution was truly random, 1 out of 10 students will choose math as his/her favorite subject.
This means that the randomization will have the null hypothesis saying that the proportion of students who will choose maths as their favourite subject = 0.1
Mathematically, it'll be written as
The null hypothesis is given as
H₀: p = 0.1
And the randomization distribution will be centred at 0.1 too.
The alternative hypothesis will now prove the theory they're looking to see in the question that
Hₐ: p < 0.1
Hope this Helps!!!
