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Ierofanga [76]
3 years ago
12

HELP ME PLS ITS DUE IN 5 MINS

Mathematics
1 answer:
Firdavs [7]3 years ago
6 0

9514 1404 393

Answer:

  • 132v^2, -v
  • 24v^6, -2v^3
  • 18v^12, 7v^6
  • -56v^14, -15v^7
  • 3v^20, -2v^10

Step-by-step explanation:

The product is the product of the numbers, multiplied by the product of the variable factors. The variable is the same in every term, so the product of the variable factors will have an exponent that is the sum of the exponents.

The difference will have a coefficient that is the difference of the coefficients.

__

(11v)(12v) = 132v^2 . . . . 11v -12v = -v

(4v^3)(6v^3) = 24v^6 . . . . 4v^3 -6v^3 = -2v^3

(9v^6)(2v^6) = 18v^12 . . . . 9v^6 -2v^6 = 7v^6

(-8v^7)(7v^7) = -56v^14 . . . . -8v^7 -7v^7 = -15v^7

(-3v^10)(-v^10) = 3v^20 . . . . -3v^10 -(-v^10) = -2v^10

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Solve the quadratic equation by factoring: 15x^2+4x-4=0
joja [24]
We can factor by grouping. To do so, we multiply the leading coefficient with the constant at the end. In other words, a times c (ax^2 + bx + c).

15*-4 = -60

Now we need to split the b term into two pieces that multiply to -60 and add to 4.

-6 and 10 will work.

Now group one part of b with the 15x^2 and the other part with -4.

(15x^2 + 10x) + (-6x - 4)

Now factor both terms.

5x(3x+2) - 2(3x+2)

3x+2 is one of our factors and 5x-2 is the other.

(3x+2)(5x-2)=0

Now just find the zeros.

3x+2 = 0
3x = -2
x = -2/3

And

5x-2 = 0
5x = 2
x = 2/5

So the answer is x = -2/3 and x = 2/5






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