Answer:
0.9954
Step-by-step explanation:
For normal distribution z score is
= ![\frac{\hat p-p}{\sigma p}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Chat%20p-p%7D%7B%5Csigma%20p%7D)
Population proportion (p) = 0.060
Sample size (n) = 285
the standard error of proportion is
= ![\sigma p = \sqrt{\frac{p\times (1 - p)}{n}}](https://tex.z-dn.net/?f=%5Csigma%20p%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%5Ctimes%20%281%20-%20p%29%7D%7Bn%7D%7D)
After putting the values into the above formula we will get
= 0.0141
Probability as the sample proportion will different from the population proportion by lower than the 4% that is
Probability = P(0.02<X<0.1) = P(-2.84<Z<2.84) = 0.9977 - 0.0023
= 0.9954
I think it should be B but I’m probably wrong so risk it if you want sorry
Answer:
0.1587
Step-by-step explanation:
Let X be the commuting time for the student. We know that
. Then, the normal probability density function for the random variable X is given by
. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,
= 0.1587
To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)
Answer:
2 hours
Step-by-step explanation:
Since he gets 59.50 every hour you'll need to see how much 59.50 can go into 110$
So, 110/59.50 = 1.8487395
You can then round this number up.
Since he's paid by the hour he'll need to work 2 hours but he'll still have a bit of money left over