Answer:
- length: 20 in
- width: 16 in
Step-by-step explanation:
Let w represent the width of the rectangle. Then the length is 5/4w, and the area is ...
A = LW
320 in² = (5/4w)(w)
256 in² = w² . . . . . . . . . multiply by 4/5
16 in = w . . . . . . . . . . . . take the square root
5/4w = 5/4(16 in) = 20 in . . . . the length
The length of the rectangle is 20 inches; its width is 16 inches.
We have a system of equations 2x - 4y = 5 and 6x - 3y = 10.
We want to eliminate one variable when we add up the equations.
If we want to eliminate the x variable, we need to multiply the top, bottom or both of the equations with a number that when the equations are added together will eliminate the x variable.
Multiply the top equation by -3.
-3(2x - 4y) = 5 * -3
-6x + 12y = -15
Now when we add the two equations together, the x's will be eliminated.
-6x + 12y = -15
6x + 6y = 10
18y = -5
The x's were eliminated.
Step-by-step explanation:
Using Pythagoras theoram,
AC²= AB²+BC²
Answer:
what is it?
Step-by-step explanation:
simply,subtract,find the domain,factor,
or write it in standard form.
