Answer:
Dy/Dx=x
(
2
ln
(
x
)
−
1
)/
ln
^2
(
x)
Step-by-step explanation:
We have this function and let's derive it in terms of x.
y =x^2/In x
Dy/Dx=(x^2/In x)'=2/lnx *(x^2)'-(x^2/In x)'=> 2
x
*ln
(
x
)
−
x
*ln
^2
(
x
)
=x
(
2
ln
(
x
)
−
1
)/
ln
^2
(
x)
Answer:
28.4
Step-by-step explanation:
Given that:
Mean, m = 31.3
Standard deviation, s = 2.8
Since, data is normally distributed :
P(x < 0.15) gives a Z value of - 1.036
Using the Zscore formula :
Z = (x - mean) / standard deviation
-1.036 = (x - 31.3) / 2.8
-1.036 * 2.8 = x - 31.3
-2.9008 = x - 31.3
-2.9008 + 31.3 = x
28.3992 = x
The temperature which correlates to the bottom 15% of the distribution is 28.4
R would equal x, as it states that lol
Answer:
58
Step-by-step explanation:
lol
use pemdas
50 + 8
58
