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3 years ago

Round the number 14.63157 to the nearest ten-thousandth.

Mathematics

2 answers:

Anit [1.1K]3 years ago

8 0

Answer:

14.6316

Step-by-step explanation:

The place value ten-thousandth falls on number 5. The following number is 7 and because 7 is greater than 5, "5" turns into 6.

Hope it helps!

IceJOKER [234]3 years ago

7 0

Answer:

14.6316

The the-thousandth is the fourth place from the decimal point so it would be 5 and you look to the right and see that the 7 is greater than 4 so it would round the number up.

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A circle has a diameter of 5 inches. A square has a side length of 5 inches. What is true about the areas of the two figures?

Neporo4naja [7]

-- They are unequal

-- The area of the circle is (pi) (radius²) = 19.63 inches² .

-- The area of the square is (side length)² = 25 inches² .

-- The area of the square is 27.3% greater than the area of the circle.

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4 years ago

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use the line graph to answer the question 9 and 10 how much did the temperature change from Sunday High to Mondays High ? what w

Marizza181 [45]

Answers:

How much did the temperature change from Sunday High to Mondays High?

Change = 4 °C

What was the difference between the high temperatures on Friday and Wednesday?

Difference = 10 °C

Explanation:

Taking into account the graph, we get that the high temperature each day is:

Sunday: -10°C

Monday: -6 °C

Tuesday: - 4 °C

Wednesday: -6 °C

Thursday: 0 °C

Friday: 4 °C

Saturday: -2 °C

So, the change from Sunday High to Mondays High can be calculated as:

Change = Monday - Sunday

Change = -6 °C - (- 10 °C)

Change = -6 °C + 10 °C

Change = 4 °C

In the same way, the difference between the high temperatures on Friday and Wednesday can be calculated as:

Difference = Friday - Wednesday

Difference = 4 °C - (-6 °C)

Difference = 4 °C + 6 °C

Difference = 10 °C

Therefore, the answers are:

How much did the temperature change from Sunday High to Mondays High?

Change = 4 °C

What was the difference between the high temperatures on Friday and Wednesday?

Difference = 10 °C

6 0

2 years ago

Solve the following system of equations. Enter the y-coordinate of the solution. Round your answer to the nearest tenth. 5x+2y=7

Rashid [163]

5x + 2y = 7....multiply by -3
-2x + 6y = 9
----------------
-15x - 6y = -21 (result of multiplying by -3)
-2x + 6y = 9
---------------add
-17x = - 12
x = 12/17 or 0.7

5x + 2y = 7
5(12/17) + 2y = 7
60/17 + 2y = 7
2y = 7 - 60/17
2y = 119/17 - 60/17
2y = 59/17
y = 59/17 * 1/2
y = 59/34 or 1.7 when rounded <====

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4 years ago

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* If the hour hand of a clock is turned counterclockwise from 2 pm to 9 am, through how many degrees will it have turned?

nikdorinn [45]

It has turned about 150 degrees going from 2-9 counter clockwise on a clock.

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4 years ago

Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

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3 years ago