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gizmo_the_mogwai [7]
3 years ago
8

at a store, the probability that a customer buys socks is 0.15. the probability that a customer buys socks given that the custom

er buys shoes is 0.20

Mathematics
1 answer:
leva [86]3 years ago
3 0

Answer: Option B

Step-by-step explanation:

First we assign a name to the events:

Event S: a customer buys socks

Event H: a customer buys shoes.

We know that :

P (S) = 0.15

We also know that the probability of S given that H occurs is:

P(S|H) =\frac{P(S\ and\ H)}{P(H)}=0.20

If two events S and H are independent then:

P (S) * P (H) = P (S\ and\ H)

This mean that if two events S and H are independent then:

P(S|H) =\frac{P(S)*P(H))}{P(H)}

P(S|H) =P(S)

We know that:

P(S|H) =0.20  and P (S) = 0.15

0.20\neq 0.15

This means that S and H events are dependent.

The answer is the option B

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The derivative (4x+1)^2
Jobisdone [24]

Answer:

\displaystyle \frac{d}{dx}[(4x + 1)^2] = 8(4x + 1)

General Formulas and Concepts:

<u>Calculus</u>

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  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle y = (4x + 1)^2

<u>Step 2: Differentiate</u>

  1. Basic Power Rule [Derivative Rule - Chain Rule]:                                       \displaystyle y' = 2(4x + 1) \cdot \frac{d}{dx}[4x + 1]
  2. Basic Power Rule [Addition/Subtraction, Multiplied Constant]:                 \displaystyle y' = 2(4x + 1) \cdot 4
  3. Simplify:                                                                                                         \displaystyle y' = 8(4x + 1)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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3 years ago
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