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irina [24]
2 years ago
8

Consider the following reaction at equilibrium. What effect will decreasing the temperature have on the system? DH=+890kJCO2(g)+

2H2O(l)<--> CH4(g)+2O2(g)a) the equilibrium constant will increaseb) the reaction will shift to the left in the direction of the reactantsc) the reaction will shift to the right in the direction of the productsd) no effect will be observed
Chemistry
1 answer:
AlladinOne [14]2 years ago
3 0

Answer:

Option B. The reaction will shift to the left in the direction of the reactants.

Explanation:

The equation for the reaction is given below:

CO₂ + 2H₂O <=> CH₄ + O₂

Enthalpy change (ΔH) = +890 KJ

The reaction illustrated by the equation is endothermic reaction since the enthalpy change (ΔH) is positive.

Increasing the temperature of an endothermic reaction will shift the equilibrium position to the right and decrease the temperature will shift the equilibrium position to the left.

Therefore, decreasing the temperature of the system illustrated by the equation above, will shift the reaction to the left in the direction of the reactants.

Thus, option B gives the right answer to the question.

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A proton is a subatomic particle carrying a charge equal to but opposite that of an electron
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True

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Determine the molality of a solution of benzene dissolved in toluene (methylbenzene) for which the mole fraction of benzene is 0
kogti [31]

Answer:

2.32 m

Explanation:

So, according to definition of mole fraction:

Mole\ fraction\ of\ benzene=\frac {n_{benzene}}{n_{benzene}+n_{toluene}}

Mole fraction = 0.176

Applying values as:

0.176=\frac {n_{benzene}}{n_{benzene}+n_{toluene}}

0.176\times ({n_{benzene}+n_{toluene}})={n_{benzene}}

So,

0.176\times n_{toluene}}=0.824\times {n_{benzene}}

{n_{benzene}}=\frac {0.176}{0.824}\times n_{toluene}}

{n_{benzene}}=0.2136\times n_{toluene}}

Also, Molar mass of toluene = 92.14 g/mol

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Mass=92.14\times n_{toluene}}\ g

Also, 1 g = 0.001 kg

So,

Mass\ of\ toluene=0.09214\times n_{toluene}}\ kg

Molality is defined as the moles of the solute present in 1 kg of the solvent.

It is represented by 'm'.

Thus,  

Molality\ (m)=\frac {0.2136\times n_{toluene}}{0.09214\times n_{toluene}}

<u>Molality of benzene = 2.32 m</u>

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3 years ago
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