1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sladkih [1.3K]
3 years ago
7

Succinate dehydrogenase catalyzes the conversion of succinate to fumarate. The reaction is inhibited by malonic acid, which rese

mbles succinate but cannot be acted upon by succinate dehydrogenase. Increasing the ratio of succinate to malonic acid reduces the inhibitory effect of malonic acid.
Chemistry
1 answer:
koban [17]3 years ago
5 0

Answer:

Succinate is the substrate, and fumarate is the product.

Explanation:

Succinate dehydrogenase is known as an enzyme complex occurs in the inner mitochondrial membrane of the eukaryotes, and many bacterial cells. This is the only enzyme that helps to contribute to both the citric acid cycle and ETC (electron transport chain). In the 6th step of the cycle, SQR utilizes the oxidation of succinate to fumarate and the reduction of ubiquinone to ubiquinol occurs.

This occurs in the inner mitochondrial membrane by pairing the 2 reactions together. Succinate and fumarate only differ in their geometrical structure around their double bond, and the other contains a trans double bond.

You might be interested in
Answer fast please <br> Which is a tissue?
lina2011 [118]

Answer:

the last picture on the right (kinda red-ish)

Explanation:

First picture: organ

Second picture: system

Third picture: organism

Last picture: tissue

Hope this helps!

6 0
4 years ago
Read 2 more answers
How many grams of sodium oxide can be synthesized from 17.4 g of sodium? assume that more than enough oxygen is present. the bal
Tatiana [17]
Equation is as follow,

<span>                          4 Na (s)  +  O</span>₂ <span>(g)    →    2Na</span>₂<span>O (s)

According to equation,

      91.92 g (4 moles) of Na produces  =  123.92 g (2 moles) of Na</span>₂O
So,
                    17.4 g of Na will produce  =  X g of Na₂O

Solving for X,
                                   X  =  (17.4 g × 123.92 g) ÷ 91.92 g

                                   X  =  23.45 g of Na₂O
7 0
3 years ago
Suggest two observations that would be made when rubidium is added to cold water.
tino4ka555 [31]

Answer:

1. Rubidium metal reacts very rapidly with water to form a colorless basic solution of rubidium hydroxide (RbOH) and hydrogen gas (H2).

2. Rubidium sinks because it is less dense than water. It reacts violently and immediately, with everything leaving the container. Rubidium hydroxide solution and hydrogen are formed.

6 0
3 years ago
For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

       = -log 6.2x10-8

       = 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0
3 years ago
A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What
Gemiola [76]

Answer:

The answer to your question:  0.7 M

Explanation:

Data

V of KOH = 90 ml

[KOH] = ?

V H2SO4 = 21.2 ml

[H2SO4] = 1.5 M

                       2KOH(aq)  +  H₂SO₄(aq)   →   K₂SO₄(aq)  +  2H₂O(l)

Molarity = moles / volume

moles of H₂SO₄ = (1.5) (21.2)

                           = 31.8

                    2 moles of KOH --------------  1 mol of H₂SO₄

                   x                           --------------  31.8 mol of H₂SO₄

                    x = (31.8)(2) / 1

                    x = 63.8 moles of KOH

Molarity = 63.8 / 90

             = 0.7 M

7 0
3 years ago
Other questions:
  • Which element has the lowest ionization energy?
    6·2 answers
  • A sample of neon gas occupies a volume of 2.8L at 1.8 atm. What would its volume be at 1.2 atm?
    12·1 answer
  • What is the speed of a wave with a frequency of 2 Hz and a wavelength of 87 m?
    5·2 answers
  • What is an aquifer mean
    11·2 answers
  • Both light and sound travel in the form of waves that are created by a transfer of ____
    7·2 answers
  • Which property of water helps islands have temperate weather throughout the year?<br><br> (1 point)
    6·1 answer
  • Methanol has the formula CH3OH. What is the predominant intermolecular force between methanol molecules?
    7·1 answer
  • Hetrocyclic reactions​
    9·1 answer
  • THE QUESTION IS NUMBER 10 PLSS HELP WILL GIVE BRAINLIEST
    9·2 answers
  • Question 9 (4 points)
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!