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Aleks04 [339]
4 years ago
5

Factor comun monomio

Mathematics
1 answer:
Annette [7]4 years ago
8 0
To find the greatest common factor (GCF) between monomials, take each monomial and write it's prime factorization. Then, identify the factors common to each monomial<span> and multiply those </span><span>common factors</span><span>together. ... The GCF!
</span>http://virtualnerd.com/pre-algebra/factors-fractions-exponents/prime-factorization-greatest-common-f...
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8 3/5 - 1 3/10 = ?<br><br> this is fractions
Semenov [28]
1)  8 \frac{3}{5} - 1 \frac{3}{10}

2)  8 \frac{6}{10} - 1 \frac{3}{10}=

3)  7\frac{3}{10}

Answer
7 \frac{3}{10}
4 0
3 years ago
Read 2 more answers
Julie gives 7 pieces of candy to each of her friends. If Julie gives all of her candy away, which amount of candy could have bee
True [87]
To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.

161/7=23
<span>162/7=23.1428571429
</span>145/7=<span>20.7142857143
128/7=</span><span>18.2857142857

Obviously, Julie cannot give a fraction of an amount of candy to someone.  So that rules out that she had 162, 145, or 128 pieces of candy.  

The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.</span>
5 0
3 years ago
Read 2 more answers
Simplify the following expression.<br> log(9x^5) + 5 log (1/x)
Darya [45]

Answer:

log9

Step-by-step explanation:

hello :

note :  a>0 and b>0

1) log(ab) = loga+logb

2) loga^n = nloga.....n in N

log(9x^5) + 5 log (1/x) = log(9x^5) +  log (1/x)^5 = log((9x^5) (1/x)^5)

                                 = log(9x^5)/(x^5)) = log9  because : (1/x)^5 = 1/x^5

6 0
3 years ago
0.2c for c=4<br> Please help me asap and provide explanation please I need help (its a quiz)
gladu [14]

Answer:

0.8

Step-by-step explanation:

Replace the c for 4, since you said that c=4

0.2(4) is what you'll get

Multiply 0.2•4 = 0.8

6 0
3 years ago
The function M(s) = 225 + 0.65s represents the material cost of manufacturing gardening scissors when s scissors are produced. T
Llana [10]

Answer:

\frac{279 + 1.8s}{s}                                                        

Step-by-step explanation:

The  material cost of manufacturing gardening scissors when s scissors are produced : M(s) = 225 + 0.65s

The labor cost for producing s scissors: L(s) = 54 + 1.15s

So, total cost of producing s scissors =  M(s)+L(s)

                                                              =  225 + 0.65s+54 + 1.15s

                                                              =  279 + 1.8s          

So, total cost for s scissors =  279 + 1.8s    

So, manufacturing cost for 1 scissor=  \frac{279 + 1.8s}{s}                                                        

Hence the manufacturing cost per scissors is  \frac{279 + 1.8s}{s}                                                        

3 0
3 years ago
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