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vivado [14]
3 years ago
8

Will give Brainliest!! pleases help, math.

Mathematics
1 answer:
oee [108]3 years ago
6 0

Answer:

a = sqrt(b^2 + c^2 - 2bc cosA) = sqrt(13^2 + 6^2 - 2 * 13 * 6 * cos 50) = sqrt(169 + 36 - 156 cos 50) ≈ sqrt(205 - 100.3) ≈ sqrt(104.7) ≈ 10.2

a ≈ 10.2

c / sin C = a / sin A

sin C = c sin A / a = 6 sin 50 / 10.2 ≈ 0.4491

C = arcsin(0.4491) ≈ 26.7

C ≈ 26.7°

B = 180 - A - C ≈ 180 - 50 - 26.7 ≈ 103.3

B ≈ 103.3°

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Fiesta28 [93]

Answer:

The table representing Relationship B is option 2

\begin{array}{ccc}Time \ (min)&&Temperature \ (^{\circ}C)\\2&&60.6\\3&&64.3\\7&&79.1\\9&&86.5\end{array}

Step-by-step explanation:

The relationship shown by Relationship A and Relationship B = The change in the temperature for a pot of water om the stove

The rate of Relationship B > The  rate of Relationship A

The table for relationship A is given as follows';

\begin{array}{ccc}Time \ (min)&&Temperature \ (^{\circ}C)\\2&&61.3\\3&&64.9\\7&&79.3\\9&&86.5\end{array}

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The rate for Relationship A, m_A = (86.5 - 61.3)/(9 - 2) = 3.6

Therefore, the rate for Relationship B > 3.6

By checking each option, we note that in option 2, the maximum value for the y-value is the same as for Relationship A, which is 86.5°C, while the minimum value for the time, <em>t</em>, is lesser than that for Relationship A, (60.6 minutes < 61.3 minutes) therefore, we get;

The rate for option 2 = (86.5 - 60.6)/(9 - 2) = 3.7

Therefore, the table that represents the Relationship B is the table for option 2

\begin{array}{ccc}Time \ (min)&&Temperature \ (^{\circ}C)\\2&&60.6\\3&&64.3\\7&&79.1\\9&&86.5\end{array}

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4 years ago
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Answer:

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Step-by-step explanation:

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