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3 years ago

BRAINLIEST PLEASE HELP ME What is the y-intercept 150 200 250 180

Mathematics

2 answers:

xeze [42]3 years ago

8 0

Answer:

250

Step-by-step explanation:

when x = 1, y = 250. That's the y-intercept

vladimir1956 [14]3 years ago

7 0

Answer: 200

Step-by-step explanation:

A y-intercept happens when x is 0. In this case, x represents the number of months, so we want to know how many stamps Carly has before starting. You can see that there is a pattern: every month, the number of stamps increases by 50.

For example, from month 1-3 (2 months), it increased 100, meaning it increased 50 per month

Now that we have that information, we have to go backwards.

At 1 month, it was 250, so at 0 months (where x = 0) it has to be 250-50, which equals 200.

Therefore, the answer is 200.

Hope this helps! :)

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Step-by-step explanation:

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Seventeen people have been exposed to a particular disease. Each one independently has a 40% chance of contracting the disease.

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3 years ago

How do I turn 1/4 into a decimal?

dybincka [34]

Answer:

No problem ;)

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Find derivative problem Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$