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2 years ago

Heeeellllllllllllp she finna call on me

Mathematics

2 answers:

Stolb23 [73]2 years ago

8 0

Answer:

its A

Step-by-step explanation:

butalik [34]2 years ago

3 0

Answer:

I think answer is a∛

Step-by-step explanation:

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The following data indicate the scores of some students in a competition:

Delicious77 [7]

Answer: The correct choice is the third choice.

First, lets look at the whiskers. They go out to the minimum and maximum. Our whiskers will need to go out to 11 and 32.

Second, lets look at the box. The range of the box is from 14 to 31 because those are the lower and upper quartile.

Finally, the middle line of the box is the median. In our case the median is 23.

These three facts lead us to chose the third option.

7 0

2 years ago

Read 2 more answers

Find the value of x in the isosceles triangle shown below Thank you!

iogann1982 [59]

And isosceles triangle always equals 180 degrees so to find the value of x what number would you need for the value to be 180

3 0

2 years ago

a surveyor measures the distance to the two landmarks as shown in the diagram what is the distance d. between the landmarks

Inessa [10]

<h3>The distance between two landmarks is 123 meters</h3>

Solution:

We have to find the distance between two landmarks

Use the law of cosines

The third side of a triangle can be found when we know two sides and the angle between them

$c^2 = a^2 + b^2 - 2ab\ cos c$

Here, angle between 90 meters and 130 meters is 65 degrees

From figure,

a = 90

b = 130

c = d

Therefore,

$d^2 = 90^2 + 130^2 - 2(90)(130)\ cos 65\\\\d^2 = 8100 + 16900 - 23400\ cos\ 65\\\\d^2 = 25000 - 23400 \times 0.4226\\\\d^2 = 25000 - 9889.267\\\\d^2 = 15110.73\\\\d = 122.92\\\\d \approx 123$

Thus, the distance between two landmarks is 123 meters

8 0

3 years ago

You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,

Vsevolod [243]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

$\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3$

The coordinates of the fourth vertex is D(4,-3)

8 0

2 years ago

The probability of rolling a '4' or a '6' on one toss of a standard six-sided die is

sesenic [268]

probability of getting 4 or 6 is 1/6 + 1/6 = 2/6 = 1/3

7 0

2 years ago