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MrMuchimi
3 years ago
9

The difference of twice a number and 10 is less than 22

Mathematics
2 answers:
valentinak56 [21]3 years ago
5 0

2(n-10)≤ 28 or n ≤ 24

Igoryamba3 years ago
5 0

Answer:

2x-10≤22

Step-by-step explanation:

2x≤22+10=32

x≤16

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Pls answer 18 20 and 22 show your work
Svetlanka [38]

Answer:

18- 300

20- 1,500

22- 300

Step-by-step explanation:

You can easily find the answer like this:

18. Multiply 60 and 100 together. The hundred is from 100%. After that, divide it by 20 because of the percent. After doing this, you should get 300.

20. 360*100=36,000 36,000/24= 1,500

22. 9*100=900 900/3=300


I hope this is what you were looking for. If you need more out of this, ask me to answer it again. :)

5 0
3 years ago
Determine if the following table represents a quadratic function.
snow_tiger [21]

Answer:

<em>The options are not visible enough (See Explanation)</em>

Step-by-step explanation:

Given

x:-  1   || 2   || 3   || 4   || 5

y:-  13 || 22 || 37 || 58 || 85

Required

Determine if the function is quadratic

Calculate the difference between the values of y

Difference = 22 - 13 = 9

Difference = 37 - 22 = 15

Difference = 58 - 37 = 21

Difference = 85 - 58 = 27

<em>The resulting difference are: 9 || 15 || 21 ||  27</em>

Next; Calculate the difference between the difference of values of y

Difference = 15 - 9 = 6

Difference = 21 - 15 = 6

Difference = 27 - 21 = 6

<em>The resulting difference are: 6 || 6 || 6</em>

<em>For the function to be quadratic, the above difference must be the same and since they are the same (6), then the function represents a quadratic function.</em>

7 0
3 years ago
In ΔSTU, the measure of ∠U=90°, SU = 7, UT = 24, and TS = 25. What ratio represents the tangent of ∠T?
Vinvika [58]

Answer:

Tan T = 7/24

Step-by-step explanation:

Firstly, please check attachment to have a picture of the triangle we are solving.

Now, we are concerned with calculating the ratio that represents the tangent of angle T.

Mathematically, the tangent of an angle is the ratio of the length of the opposite to the length of the adjacent.

In this question, our opposite is 7 while the adjacent is 24.

Thus Tan T = 7/24

6 0
4 years ago
Please i really need help​
Genrish500 [490]

Answer:

-7, -6, -4, -2, 0, 2, 5, 7, 8, 9

Step-by-step explanation:

4 0
3 years ago
Match the expressions with their equivalent simplified expressions.
Tasya [4]

Answer:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}


Step-by-step explanation:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}

\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}

\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}

\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}

\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}

\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}

Thus,

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}

3 0
3 years ago
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