F(5) = - 2f(4) + 1
f(4) = -2f(3) + 1
f(3) = -2f(2) + 1
f(2) = -2f(1) + 1
Therefore:
f(2) = -2(3) + 1 = -5
f(3) = -2(-5) + 1 = 11
f(4) = -2(11) + 1 = -21
Therefore f(5) = -2(-21) + 1 = 43
Answer:
Point A(9, 3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Coordinates (x, y)
- Functions
- Function Notation
- Terms/Coefficients
- Anything to the 0th power is 1
- Exponential Rule [Rewrite]:
- Exponential Rule [Root Rewrite]:
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative of a constant is 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Chain Rule]: ![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<em />
<em />
<u>Step 2: Differentiate</u>
- [Function] Rewrite [Exponential Rule - Root Rewrite]:

- Basic Power Rule:

- Simplify:

- [Derivative] Rewrite [Exponential Rule - Rewrite]:

- [Derivative] Rewrite [Exponential Rule - Root Rewrite]:

<u>Step 3: Solve</u>
<em>Find coordinates of A.</em>
<em />
<em>x-coordinate</em>
- Substitute in <em>y'</em> [Derivative]:

- [Multiplication Property of Equality] Multiply 2 on both sides:

- [Multiplication Property of Equality] Cross-multiply:

- [Equality Property] Square both sides:

<em>y-coordinate</em>
- Substitute in <em>x</em> [Function]:

- [√Radical] Evaluate:

∴ Coordinates of A is (9, 3).
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Derivatives
Book: College Calculus 10e
Answer:
2:1/2
5:16/24
10:Movie B
11:Movie D
12:2/3
I can't see 29. If you show it, then i will solve it.
Step-by-step explanation:
The number of zeros of the quadratic functions, considering their discriminant, is given as follows:
- discriminant = 0: 1 Real number solution.
- discriminant = -36: 0 Real number solutions.
- discriminant = 3: 2 Real number solutions.
- discriminant = 2: 2 Real number solutions.
- discriminant = 100: 2 Real number solutions.
- discriminant = -4: 0 Real number solutions.
<h3>What is the discriminant of a quadratic equation and how does it influence the solutions?</h3>
A quadratic equation is modeled by:

The discriminant is:

The solutions are as follows:
- If
, it has 2 real solutions.
- If
, it has 1 real solutions.
- If
, it has 0 real solutions.
Hence, for the given values of the discriminant, we have that:
- discriminant = 0: 1 Real number solution.
- discriminant = -36: 0 Real number solutions.
- discriminant = 3: 2 Real number solutions.
- discriminant = 2: 2 Real number solutions.
- discriminant = 100: 2 Real number solutions.
- discriminant = -4: 0 Real number solutions.
More can be learned about quadratic functions at brainly.com/question/24737967
#SPJ1
Answer:
B. 4√3
Step-by-step explanation:
