Answer:
The magnitude of the electric field is
Explanation:
From the question we are told that
The electric potential is
Generally electric filed is mathematically represented as
So
at (x,y,z) = (1.0, 1.0, 1.0)
The magnitude of the electric field is
Answer:
(a) 1294.66 m
(b) 88.44°
Explanation:
d1 = 580 m North
d2 = 530 m North east
d3 = 480 m North west
(a) Write the displacements in vector forms
The resultant displacement is given by
magnitude of the displacement
d = 1294.66 m
(b) Let θ be the angle from + X axis direction in counter clockwise
θ = 88.44°
Answer:
19 contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose.
Explanation:
Complete Question
Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol.
One contraction cycle in muscle requires 67 kJ, and the energy from the combustion of glucose is converted with an efficiency of 45% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose? Round your answer to the nearest whole number.
Complete combustion of glucose liberates 2870 kJ/mol.
Complete combustion of one mole of glucose will liberate 2870 × 1 = 2870 kJ
The energy from the combustion of glucose is converted with an efficiency of 45% to contraction.
So, the amount of energy from the combustion of one mole of glucose that is converted to contraction is
45% × 2870 = 1,291.5 kJ
One contraction cycle requires 67 kJ of energy, so, 1291.5 kJ will cause
(1291.5/67) contraction cycles = 19.28 contraction cycles = 19 contraction cycles to the nearest whole number.
Hope this Helps!!!
Answer:
binding energy is 99771 J/mol
Exlanation:
given data
threshold frequency = 2.50 × Hz
solution
we get here binding energy using threshold frequency of the metal that is express as
..................1
here E is the energy of electron per atom and h is plank constant i.e. and x is binding energy
and here N is the Avogadro constant =
so E will
E =
so put value in equation 1 we get
= 2.50 × ×
solve it we get
x = 99770.99
so binding energy is 99771 J/mol