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3 years ago

12

One Pro for supplements is the cost. True Or False

1 answer:

Nat2105 [25]3 years ago

8 0

Answer:

False

Explanation:

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Which of the following is true about the Sun?

bekas [8.4K]

A. The Sun is the only star in the Solar System. This is the only star we know of.
I hope this helps!!

6 0

2 years ago

A flat circular plate of copper has a radius of 0.262 m and a mass of 61.5 kg.

Evgesh-ka [11]

Answer:

0.031 m

Explanation:

Density of copper = ρ = 8960 kg/m³

r = Radius = 0.262 m

m = Mass of plate = 61.5 kg

v = Volume of plate = Volume of cylinder = πr²h

$\rho=\frac{m}{v}\\\Rightarrow 8940=\frac{61.5}{\pi r^2h}\\\Rightarrow h=\frac{61.5}{\pi 0.262^2\times 8940}\\\Rightarrow h=0.031\ m$

So, thickness of plate is 0.031 m

5 0

3 years ago

Alice's friends Bob and Charlie are having a race to a distant star 10 light years away. Alice is the race official who stays on

hodyreva [135]

Solution :

The distance between the starting point and the end point, $L_0$ = 10 light years

But due to the relativistic motion of Bob and Charlie, the distance will be reduced following the Lorentz contraction. The contracted length will be different since they are moving with different speeds.

For Bob,

Speed of Bob's rocket with respect to Alice, $L_b = 0.7 \ c$

So the distance appeared to Bob due to the length contraction,

$L_b=L_0\sqrt{1-\frac{V_b^2}{c^2}$

$L_b=10\times \sqrt{1-0.49} \ Ly$

$=7.1 \ Ly$

Therefore, the time required to finish the race by Bob is

$t_b = \frac{L_b}{V_b}$

$=\frac{7.1 \ c}{0.7 \ c}$

= 10.143 year

For Charlie,

Speed of Charlie's rocket with respect to Alice, $L_c = 0.866 \ c$

So the distance appeared to Charlie due to the length contraction,

$L_b=L_0\sqrt{1-\frac{V_c^2}{c^2}$

$L_b=10\times \sqrt{1-0.75} \ Ly$

$=5 \ Ly$

The time required to finish the race by Charlie is

$t_b = \frac{L_c}{V_c}$

$=\frac{5 \ c}{0.866 \ c}$

= 5.77 year

5 0

3 years ago

A 13500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the

Mekhanik [1.2K]

Answer

given,

mass of the jet airplane = 13500 kg

Force on the plane = 35700 N due north

force from wind = 15300 N in direction 80.0° south of west.

Force = $35700 \vec{j} N$

force by wind = $15300(-cos \theta \vec{i}-sin \theta \vec{j})$ N

= $15300(-cos 80^0 \vec{i}-sin 80^0 \vec{j})$ N

net force on the jet airplane(ma)

$m a = 35700 \vec{j} + 15300(-cos 80^0 \vec{i}-sin 80^0 \vec{j})$

$\vec{a} = \dfrac{35700}{13500} \vec{j} + \dfrac{15300}{13500}(-cos 80^0 \vec{i}-sin 80^0 \vec{j})$

$\vec{a} = 2.64\vec{j} -0.197 \vec{i} - 1.116 sin 80^0 \vec{j})$

$\vec{a} = -0.197 \vec{i} + 1.524 \vec{j}$

$a = \sqrt{-0.197^2+1.524^2}$

a = 1.54 m/s²

$\theta = tan^{-1}(\dfrac{-1.524}{0.197})$

$\theta = -82.63^0$

3 0

3 years ago

How does a toy use energy?

34kurt

Answer:

Kinetic Energy,have a good day!

4 0

3 years ago