The material that the cylinder is made from is Butyl Rubber.
<h3>What is Young's modulus?</h3>
Young's modulus, or the modulus of elasticity in tension or compression, is a mechanical property that measures the tensile or compressive strength of a solid material when a force is applied to it.
<h3>Area of the cylinder</h3>
A = πr²
<h3>Young's modulus of the cylinder</h3>
Where;
e is extension
When 5 kg mass is applied, the extension = 10 cm - 9.61 cm = 0.39 cm = 0.0039 m.
When the mass is 50 kg,
extension = 10 cm - 7.73 cm = 2.27 cm = 0.0227 m
The Young's modulus is between 0.001 GPa to 0.002 GPa
Thus, the material that the cylinder is made from is Butyl Rubber.
The magnitude of the force on positive charges will be and the magnitude of the force on the negative charge is .
Explanation:
Given:
The value of the charges, .
The length of each side of the triangle, .
Consider a equilateral triangle , as shown in the figure. Let two point charges of magnitude are situated at points and and another point charge is situated at point .
The value of the force on the charge at point due to charge at point is given by
The value of the force on the charge at point due to charge at point is given by
The net resultant force on the charge at point is given by
The value of the force on the charge at point due to charge at point is given by
The value of the force on the charge at point due to charge at point is given by
The net resultant force on the charge at point is given by
The value of the force on the charge at point due to charge at point is given by
The value of the force on the charge at point due to charge at point is given by
The net resultant force on the charge at point is given by
Substitute for , for and for in equation (1), we have
Substitute for , for and for in equation (2), we have
Substitute for , for and for in equation (3), we have
where L is the length of the pendulum and g the gravitational acceleration.
In this problem,
L = 0.625 m
g = 9.81 m/s^2
Substituting into the equation, we find
2. 54,340 oscillations
The total number of seconds in a day is given by:
So in order to find the number of oscillations of the pendulum in one day, we just need to divide the total number of seconds per day by the period of one oscillation:
3. 0.842 m
We want to increase the period of the pendulum by 16%, so the new period must be
Now we can re-arrange the equation for the period of the pendulum, using T=1.84 s, to find the new length of the pendulum that is required to produce this value of the period: